Answer:
A. the internal energy stays the same
Explanation:
From the first law of thermodynamics, "energy can neither be created nor destroyed but can be transformed from one form to another.
Based on this first law of thermodynamic, the new internal energy of the gas is the same as the internal energy of the original system.
Therefore, when the partition separating the two halves of the box is removed and the system reaches equilibrium again, the internal energy stays the same.
<span>The gravity of earth depends on the magnetism from its core. as this magnetism increases, the magnitude of the gravity increases.</span>
Answer:
there's a link to answer
Explanation:
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Answer:
Vi = 8.28 m/s
Explanation:
This problem is related to the projectile motion.
As we know there are two components of motion associated with this, the horizontal component and vertical component.
The horizontal distance covered by the ball is
Vx*t = x
Vx*t = 5.3
Vx = 5.3/t eq. 1
Also we know that
Vx = Vicos(60)
Vx = Vi*0.5 eq. 2
equate eq. 1 and eq. 2
5.3/t = Vi*0.5
5.3/0.5 = Vi*t
Vi*t = 10.6 eq. 3
The vertical distance is
Vy = y1 + Vyi*t - 0.5gt²
also we know that
Vyi = Visin(60)
Vyi = Vi*0.866
It is given that V1 = 1.9 m and and Vy = 3 m is the vertical distance
3 = 1.9 + Vi*0.866*t - 0.5gt²
3 = 1.9 + Vi*0.866*t - 0.5(9.8)t²
3 = 1.9 + 0.866(Vi*t) - 0.5(9.8)t²
3 = 1.9 + 0.866(Vi*t) - 0.5(9.8)t²
1.1 = 0.866(Vi*t) - 4.9t²
0.866(Vi*t) = 4.9t² + 1.1
substitute Vi*t = 10.6 in above equation
0.866(10.6) = 4.9t² + 1.1
9.18 = 4.9t² + 1.1
4.9t² = 8.08
t² = 8.08/4.9
t² = 1.648
t = 1.28 sec
Finally, initial speed can be found by substituting the value of t into eq. 3
Vi*t = 10.6
Vi = 10.6/t
Vi = 10.6/1.28
Vi = 8.28 m/s
Explanation:
The given data is as follows.
![U_{a} = 5.4 \times 10^{-8} J](https://tex.z-dn.net/?f=U_%7Ba%7D%20%3D%205.4%20%5Ctimes%2010%5E%7B-8%7D%20J)
![W_{/text{a to b}} = -1.9 \times 10^{-8} J](https://tex.z-dn.net/?f=W_%7B%2Ftext%7Ba%20to%20b%7D%7D%20%3D%20-1.9%20%5Ctimes%2010%5E%7B-8%7D%20J)
Electric potential energy (
) = ?
Formula to calculate electric potential energy is as follows.
= ![5.4 \times 10^{-8} J - (-1.9 \times 10^{-8} J)](https://tex.z-dn.net/?f=5.4%20%5Ctimes%2010%5E%7B-8%7D%20J%20-%20%28-1.9%20%5Ctimes%2010%5E%7B-8%7D%20J%29)
= ![7.3 \times 10^{-8} J](https://tex.z-dn.net/?f=7.3%20%5Ctimes%2010%5E%7B-8%7D%20J)
Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is
.