Figure 1
Perimeter
3 * (1/2) * (6π) + (1/2) * (18π) = 18π cm
Area
3 * (1/2) * ((3 ^ 2) π) + (1/2) * ((9) ^ 2π) = 54π cm ^ 2
Figure 2
Perimeter
6 * (1/2) * (4π) + 2 * (4) = (12π + 8) cm
Area
3 * (4 * 4) = 48 cm ^ 2
Figure 3
Perimeter
2 * (1/2) * (6π) + (1/2) * (12π) + 2 * (6) = (12π + 12) cm
Area
2 * (6 * 6) + (1/2) * ((6) ^ 2π) = (18π + 72) cm ^ 2
Let's solve for i.
9x + 7i <3 (3x+7u)
First add -9x to both sides.
7i + 9x + −9x < 21u + 9x + −9x
7i < 21u
Then Divide both sides by 7.
7i/7 < 21u/7
The answer is i < 3u
I’m not sure is it correct or not but I say the answer is 4
Area = length * width
(10x + 6)(9x + 8)
Multiple (I used rainbow method)
10x * 9x = 90x^2
10x * 8 = 80x
6 * 9x = 54x
6 * 8 = 48
90x^2 + 80x + 54x + 48
90x^2+ 134x + 48
The area is 90x^2 + 134x + 48