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Ede4ka [16]
3 years ago
5

If I have $65 in the bank add 7% and i add $15 each year,how much do i have in 8 years?

Mathematics
2 answers:
Dovator [93]3 years ago
7 0
I think it is 556.40 because I multiple 65 by 7% then I added 4.55 by 65 then I multiple it by 8
SCORPION-xisa [38]3 years ago
3 0
You would have 575 dollars in 8 years
You might be interested in
The ratio of teachers to students on a field trip to New York City is 2 to 9. If there are 243 students on the trip,
Veseljchak [2.6K]

Answer:

54 teachers

Step-by-step explanation:

Step one:

given data

The ratio of teachers to students on a field trip to New York City is 2 to 9.

That is the ratio is 2:9

We are told that there are 243 students

Required

We want to find the number of teachers

Step two:

Applying the part to part method we have

let the number of teachers be x

2/9= x/243

cross multiply we have

9x= 243*2

9x= 486

divide both sides by 9

x= 54

Hence there are 54 teachers

4 0
3 years ago
Determine the first four terms of the sequence in which the nth term is...
Anon25 [30]

Answer:

1/5, 1/6, 1/7, 1/8

Step-by-step explanation:

The formula for the sequence is (n+3)!/ (n+4)!

The first terms uses n=1

a1 = (1+3)!/ (1+4)! = 4!/5! = (4*3*2*1)/(5*4*3*2*1) = 1/5


The first terms uses n=2

a2 = (2+3)!/ (2+4)! = 5!/6! = (5*4*3*2*1)/(6*5*4*3*2*1) = 1/6


The first terms uses n=3

a3 = (3+3)!/ (3+4)! = 6!/7! = (6*5*4*3*2*1)/(7*6*5*4*3*2*1) = 1/7


The first terms uses n=4

a4 = (4+3)!/ (4+4)! = 7!/8! = (7*6*5*4*3*2*1)/(8*7*6*5*4*3*2*1) = 1/8

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=55%20%5Cfrac%7B6%7D%7B9%3F%7D%20%20%5Ctimes%2066%20%5Cfrac%7B5%7D%7B6%7D%20" id="TexFormula1"
JulsSmile [24]

Answer:

Step-by-step explanation:

If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.

55 2/3 * 66 5/6

One of the ways to get the answer is to use decimals

55.666666667 * 66.833333333 = 3720.38889

Another way to do this problem is to break up one of the numbers

55 2/3 (66 + 5/6)   You can do this if you know how to use the distributive property.

55 2/3 * 66 + 55 2/3 * 5/6

( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6

167/3 * 66 + 167 / 3 * 5/6

167 * 22 + (167 * 5 / (3 * 6)

3674 + 835 / 18

3674 + 46 7/18

3720 7/18

If none of these seem right and you have choices, please list them.  

6 0
4 years ago
The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by
Vikentia [17]

The answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\

suppose x = m.\frac{\pi}{6}+55 and \frac{\pi}{2} = 90 degree

We know, cos(x+90°) = - sin(X)

⇒ cos((m.\frac{\pi}{6})+55+90degree)degree = -sin((m.\frac{\pi}{6})+55)

⇒ t = sin((m.\frac{\pi}{6})+55)

Hence the answer will be t = sin((m.\frac{\pi}{6})+55) average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

To learn more visit:

brainly.com/question/27441712

#SPJ4

3 0
2 years ago
From a point 100 m from a building the angles of elevation of the top and bottom of a flagpole atop a building are 54.5 degrees
AnnZ [28]

Answer:60ft

Step-by-step explanation:The height of the flagpole is approximately  

60

feet.

Explanation:

Always try to draw a diagram.

enter image source here

We know that there is a right angle between the ground and the building. Therefore, we can use the 3 basic trig ratios instead of the sine or cosine law to solve this problem.

Since the angle in the corner of the larger right triangle measures  

42

˚

, the top angle in this triangle measures  

180

˚

−

90

˚

−

42

˚

=

48

˚

.

By basic trig ratios, we can find the height of the building with the flag pole on top, call it  

H

.

tan

42

˚

1

=

H

500

H

=

500

tan

42

˚

I would keep it in exact form until the last step.

We now devise an expression for the height of the building (without the flag pole). Call it  

a

tan

38

˚

1

=

a

500

a

=

500

tan

38

˚

We can now state that

h

=

H

−

a

h

=

500

tan

42

˚

−

500

tan

38

˚

h

≈

59.559

≈

60

feet

Hopefully this helps!

Answer link

EET-AP

Apr 10, 2017

The flagpole is  

60

f

t

in height to the nearest foot.

Explanation:

1) The flagpole is on top of a building.

2)Angles of elevation both measured from point  

500

f

t

from building

3) Angle of elevation to the top of building is  

38

d

e

g

4) Angle of elevation to the top of flagpole is  

42

d

e

g

The information above will provide us with two right angle triangles, one smaller one inside a larger one.

Both will have a base of  

500

f

t

.

The smaller triangle will have a base angle  

β

of  

38

deg opposite the  

90

deg, and the larger triangle will have a base angle  

β

of  

42

deg.

From this information we can find the heights of the building and the building + pole using the definition of the tangent of the two base angles  

β

:

tan

(

β

)

=

o

p

p

a

d

j

where the  

o

p

p

is the height and the  

a

d

j

is the  

500

f

t

o

p

p

(

b

u

i

l

d

)

=

tan

(

38

)

⋅

(

500

f

t

)

=

390.6

f

t

=

height of building

o

p

p

(

f

l

a

g

)

=

tan

(

42

)

⋅

(

500

f

t

)

=

450.2

f

t

=

height of building + pole

Then to the nearest foot the height of the flagpole is:

450.2

f

t

−

390.6

f

t

=

60

f

t

4 0
3 years ago
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