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Kay [80]
2 years ago
15

Solve for c y-(-10-c)=z

Mathematics
2 answers:
raketka [301]2 years ago
8 0
Distribute
y+10+c=z
minus y from both sides
10+c=z-y
minus 10 both sides
c=z-y-10
elena55 [62]2 years ago
6 0
Y+10+c=z
Y=z-10-c
C=z-10-y
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Chapman’s brickyard sells bricks and blocks. A brick costs $0.38 and a block costs $1.56. The brickyard filled a $24.80 order, w
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Answer:

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Step-by-step explanation:

From given information it seems , we need to determine number of bricks and number of blocks.

lets assume number of bricks = x

and number of blocks = y

since total items in brickyard is 28

⇒  number of bricks + number of blocks = 28

⇒ x + y = 28         ----------------------- equation 1

Given that cost of 1 brick = $0.38  and cost of 1 block =$1.56

so cost of x bricks = cost of 1 brick × x = 0.38x

And cost of y blocks = cost of 1 block × y = 1.56y

total cost of 28 items order = $24.80

total cost of 28 items = cost of x bricks + cost of y blocks

⇒0.38x + 1.56y = 24.80 ----------------equation 2

Now we are having following two equations

x + y = 28         ----------------------- equation 1

0.38x + 1.56y = 24.80 ----------------equation 2

from equation 1 we get x = 28 - y , substituting this value of x in equation 2 we get

0.38(28 - y) + 1.56y =  24.80

⇒10.64-0.38y+1.56y= 24.80

⇒1.18y = 24.80 - 10.64

⇒y = 14.16÷1.18 = 12

substituting value of y in equation 1 we get

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⇒x = 16

hence  number of bricks = x  = 16 and number of blocks = y = 12



4 0
3 years ago
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