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3 years ago

Find the value of x in the diagram below

Mathematics

2 answers:

noname [10]3 years ago

7 0

X=26
because a straight line is 180 degrees
so you will
1) equal 4x-8, 34, and 76-x to 180
2) combine like factors
3) subtract 102 from 180
4) divide by 3x

Ghella [55]3 years ago

4 0

Answer:

x=26

Step-by-step explanation:

4x-8+34+76-x=180

4x-x-8+34+76=180

3x+102=180

3x=180-102

3x=78

x=78/3

x=26

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weqwewe [10]

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4 years ago

Ava estimates that 475 songs will fit on her iPad. The actual amount of songs that fit is 350. Find her percent of error.

alukav5142 [94]

Given:

Ava estimates that 475 songs will fit on her iPad.

The actual amount of songs that fit is 350.

To find:

The percent of error.

Solution:

We know that,

$\text{Percent error}=\dfrac{\text{Estimated values - Actual value}}{\text{Actual value}}\times 100$

Putting the given values, we get

$\text{Percent error}=\dfrac{475-350}{350}\times 100$

$\text{Percent error}=\dfrac{125}{350}\times 100$

$\text{Percent error}=\dfrac{250}{7}$

$\text{Percent error}\approx 35.71\%$

Therefore, the percent of error is 35.71%.

3 0

3 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

3 years ago

Select the graph that would represent the best presentation of the solution set.<br> \absP > 3

m_a_m_a [10]

Answer:

Step-by-step explanation:

there's no graph selection attached. Can you upload it and then I can help?

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2 years ago

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larisa86 [58]

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4.

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4 years ago