Yes.
It can be proved by contradiction.
Let:
a - a rational number
b - an irrational number
c - the sum of a and b

Let assume that c is a rational number. Then a and c can be expressed as fractions with integer numerator and denominator:

where


Since

are all integers, then the products

and the difference

are integers as well. It means that the number

is a rational number, but this on the other hand contradicts the earlier assumption that

is an irrational number. Therefore

must be an irrational number.
Answer: 1/2
Explanation:
1/2 is 50
1/4 is 25
25<50
Answer:
Step-by-step explanation:
㏒(6)-㏒(2)=㏒(6/2)=㏒ 3
Answer:
1.6 hours so 96 minutes
Step-by-step explanation:
Answer:
95%
Step-by-step explanation: