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3 years ago

HELP ME PLEASE!!!!!!

Mathematics

1 answer:

Phoenix [80]3 years ago

8 0

Answer:

<em>The remainder is -61</em>

Step-by-step explanation:

The polynomial remainder theorem states that the remainder of the division of a polynomial f(x) by (x-r) is equal to f(r).

The given polynomial is:

$f(x) = 4x^3 - 6x^2 + 3x + 1$

We need to find the remainder when f(x) is divided by x+2. According to the above-mentioned theorem, we only need to find f(-2) as follows:

$f(-2) = 4(-2)^3 - 6(-2)^2 + 3(-2) + 1$

$f(-2) = 4(-8) - 6(4) - 6 + 1$

$f(-2) = -32 - 24 - 6 + 1=-61$

The remainder is -61

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G(r)=−5r+13<br> g(3)=<br><br> I'm still confused on how to do this

SashulF [63]

If you're solving for g then move all terms to the left side and set equal to zero. Then set each factor equal to zero.

And your answer becomes $g=\frac{5r}{r-39}$

If you're solving for r then then move all terms to the left side and set equal to zero. Then set each factor equal to zero and your answer is $r=\frac{39g}{g-5}$

6 0

4 years ago

3 divided by what gives you 24<br>

Anarel [89]

What divided by 3 equals 24? In other words, you have an unknown number (X), and then if you divide that X by 3 you get 24. Then what is that X?

The equation to calculate what divided by 3 equals 24 is as follows:

X/3 = 24

Where X is the answer. When we solve the equation by multiplying each side by 3, you get get:

X = 72

Therefore, the answer to what divided by 3 equals 24 is 72.

Hope that helps

7 0

3 years ago

If a polynomial function f(x) has roots 3+root5 and -6, what must be a factor of f(x)? (X+(3-root5) (x-(3-root5)) (x+(5+root3))

belka [17]

Answer:

$(x-(3+\sqrt5))$ or $(x-3-\sqrt5)$ is a factor of the given polynomial.

Step-by-step explanation:

Let us learn the concept with an example first.

Let the polynomial be a quadratic function $g(x)$ .

$g(x) = x^{2} -5x+6$

The roots of $g(x)$ are 2 and 3.

Putting $x= 2\ in \ g(x)$

$2^2-5\times 2+6 = 4-10+6 =0$

Putting $x= 3\ in \ g(x)$

$3^2-5\times 3+6 = 9-15+6 =0$

Putting x = 2 or x = 3, g(x) = 0 $\therefore$ The roots of equation g(x) are 2 and 3.

Now, let us try to factorize g(x):

$x^{2} -2x-3x+6\\\Rightarrow x(x -2)-3(x-2)\\\Rightarrow (x-3)(x-2)$

so, the equation can be written as:

$g(x) = x^{2} -5x+6=(x-3)(x-2)$ where 3 and 2 are the roots of equation.

The factors are (x-3) and (x-2).

$\therefore$ for the polynomial f(x) which has roots $3+\sqrt5\ and\ -6$ will have a factor:

$(x-(3+\sqrt5))$ or $(x-3-\sqrt5)$

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4 years ago

What is the sum of 7/6 and 5/8

zmey [24]

Answer:

1 19/24

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A force of 128 lb is required to hold a spring stretched 2 ft beyond its natural length. How much work W is done in stretching i

Agata [3.3K]

We have that the workdone in stretching natural length to is mathematically given as

W=9/2lbft

<h3>Workdone in stretching natural length</h3>

Question Parameters:

A force of 128 lb is required to hold a spring stretched 2 ft <em>beyond </em>its natural length.
Stretching it from its natural length to 9 inches beyond its natural length

Generally the Hookes equation for the Force is mathematically given as

F=Kx

Where

3.2lb=2ft*k

Thereofore

k=16

Force becomes

f=kx

f=16x

Hence

$W=8[x^2]^{3/4}_{0}$

W=9/2lbft

For more information on Length visit

brainly.com/question/2096451

6 0

2 years ago