Ask question

Ask question

All categories

wolverine [178]

3 years ago

5

What is the sum of 7/6 and 5/8

2 answers:

fenix001 [56]3 years ago

8 0

Answer:

43/24

Mixed form

1 19/24

Step-by-step explanation:

zmey [24]3 years ago

7 0

Answer:

1 19/24

Step-by-step explanation:

You might be interested in

When Jill woke up, the temperature was -3 C. By noon the temperature had increased by 8 C.

AlekseyPX

-3+8.

We know that the temperature /was/ -3, so it was 3 under zero. It has /risen/ by 8, meaning we have added 8 degrees to whatever the starting temperature was.

We can find out how much the temperature is right now: it was -3, went through -2, -1, 0, 1, 2, 3, 4, and now its at 5 degrees. Thats risen by 8 degrees, right? And -3+8 is the same as 8-3 (commutative property of addition, since we basically did 8+(-3)) which equals 5, so we know that we got the correct answer. :)

3 0

3 years ago

Sansa wrote this expression:

NISA [10]

Answer:

34 is the answer

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Abigail heard on the weather report that there is a 40% chance that it will rain tomorrow and a 50% chance that it will be cloud

ivann1987 [24]

Random numbers from 0-9 with 0, 1, 2, and 3 being rain and 4, 5, 6, 7, and 8 being cloudy.

7 0

3 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago

What were the headlines after a mad scientist trained two eggs to attack a candy store with sharp sticks

Vladimir79 [104]

It was "eggs spear a mint".

Hope This Helps You!

Good Luck Studying :)

8 0

3 years ago