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Hoochie [10]
3 years ago
9

how many gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antif

reeze?
Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:m(.70)+80(.25)=.6(m+80)

.7m+20=.6m+48

.1m=28

m=28/.1=280 gallons of 25% antifreeze needed

Step-by-step explanation:

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