how many gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antif
reeze?
1 answer:
Answer:m(.70)+80(.25)=.6(m+80)
.7m+20=.6m+48
.1m=28
m=28/.1=280 gallons of 25% antifreeze needed
Step-by-step explanation:
You might be interested in
Answer:
True.
Step-by-step explanation:
Answer:
5u-15=10 |+15
5u=25 |:5
u=5
The solution is 25
I hope it helps
have anice day
Answer:
6,8,9
Step-by-step explanation:
6,8,9
any sum of two sides are bigger than the third side
Answer:
= (x + 5)(x - 9)
Step-by-step explanation:
5x = 8x+30
5x-8x+30 = 0
-3x=-30
x=-10
