how many gallons of a 70% antifreeze solution must be mixed with 80 gallons of 25% antifreeze to get a mixture that is 60% antif
reeze?
1 answer:
Answer:m(.70)+80(.25)=.6(m+80)
.7m+20=.6m+48
.1m=28
m=28/.1=280 gallons of 25% antifreeze needed
Step-by-step explanation:
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5u-15=10 |+15
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Step-by-step explanation:
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