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4 years ago

14

Which expression would represent the cost of one CD, If the total cost for three of them is $36? O 3(36) 36 - 3 36 3 3+ 36

2 answers:

SOVA2 [1]4 years ago

5 0

Answer: It is c i just got it right

Step-by-step explanation:

Sveta_85 [38]4 years ago

4 0

Answer:

How could you represent the total amount of money spent on bread? ... When someone is having trouble with algebra, they may say, “I don't speak math! ... and we want to be able to translate these phrases into algebraic expressions. Consider ... 36. 3. Write a function rule for the table. hours. 0. 1. 2. 3 cost. 15. 20. 25. 30. 4.

Step-by-step explanation:

How could you represent the total amount of money spent on bread? ... When someone is having trouble with algebra, they may say, “I don't speak math! ... and we want to be able to translate these phrases into algebraic expressions. Consider ... 36. 3. Write a function rule for the table. hours. 0. 1. 2. 3 cost. 15. 20. 25. 30. 4.

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<img src="https://tex.z-dn.net/?f=The%20%5C%3A%20%20value%20%20%5C%3A%20of%20%20%5C%3A%20%20%5Csqrt%7B6%20%2B%20%20%5Csqrt%7B6%2

saul85 [17]

$\large\underline{\sf{Solution-}}$

<u>Let us assume that:</u>

$\sf \longmapsto x = \sqrt{6 + \sqrt{6 + \sqrt{6 + ... \infty } } }$

We can also write it as:

$\sf \longmapsto x = \sqrt{6 + x }$

Squaring both sides, we get:

$\sf \longmapsto {x}^{2} =6 + x$

$\sf \longmapsto {x}^{2} - x - 6 =0$

By splitting the middle term:

$\sf \longmapsto {x}^{2} - 3x + 2x - 6 =0$

$\sf \longmapsto x(x - 3) + 2(x - 3 ) =0$

$\sf \longmapsto (x+ 2)(x - 3 ) =0$

<u>Therefore:</u>

$\longmapsto\begin{cases} \sf (x+ 2) =0 \\ \sf (x - 3) = 0 \end{cases}$

$\sf \longmapsto x = - 2,3$

<u>But x cannot be negative. </u>

$\sf \longmapsto x = 3$

Therefore, the value of the expression is 3.

$\large\underline{\sf{Verification-}}$

Given:

$\sf\longmapsto x=3$

We can also write it as:

$\sf\longmapsto x = \sqrt{9}$

$\sf\longmapsto x = \sqrt{6+3}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{9}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+3}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{9}}}$

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+3}}}$

This pattern will continue.

$\sf\longmapsto x = \sqrt{6 + \sqrt{6+\sqrt{6+...\infty}}}$

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