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Alina [70]
2 years ago
12

Please help me hurry please

Mathematics
1 answer:
aalyn [17]2 years ago
5 0

Answer:

y = root under 24 (evaluate it if necessary)

or y = 2 root 6

Step-by-step explanation:

Let the reference angle be x

for the triangle in left,

b = 6-4 = 2

Now,

taking x as refrence angle,

cosx = b/h

or, cosx = 2/h

again,

for the bigger triangle,

taking x as reference angle,

cosx = b/h

or, cosx = b/6

As we can see base of bigger triangle is equal to hypotenuse of triangle at the left,

Let's suppose its a

so, cosx = a/6 = 2/a

now,

a/6 = 2/a

or, a² = 12

now,

for bigger triangle, using pythagoras theorem,

h² = p²+b²

or, 6² = y² + a²

or, 36 = y² + 12

or, y² = 24

so, y = root under 24

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Read 2 more answers
The sum of two numbers is odd. Can the quotient of the two numbers be an odd number?
Natalka [10]

Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

let 2k + 1 be an odd number, and 2j + 1 other.

the product is:

(2k + 1)*(2j + 1) = 2*(2*k*j + k + j) + 1

and as k and j are integers, also does 2*k*j + k + j, so:

2*(2*k*j + k + j) + 1 is an odd number.

This says that the product of two odd numbers is always odd, then we never can have that the quotient between an even number and an odd number is odd.

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3 years ago
Determine if triangle XYZ with coordinates X (1, 1), Y (5, 6), and Z (6, 2) is a right triangle. Use evidence to support your cl
AveGali [126]
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