Answer:
-4 ≤ f () ≤ 4
Step-by-step explanation:
The range of a function is the allowed y-values of the function.
We can simply look at the periodic function below and see that the y-value ranges from a negative 4 to a positive 4. It oscillates betwen -4 and 4. That is the range.
We can say -4 ≤ f () ≤ 4
Last answer choice is right.
*** <u>NOTE:</u> it is a type, not "0", rather ""
Answer:
Regression Line is given by,
y = 22.909 + 0.209 x
The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Step-by-step explanation:
The equation of Regression equation is of the form of:
y = a + bx
where, a is intercept and b is slope
The formula for a and b is given by,
Here, ∑X = 1149.8, ∑Y = 377.2, ∑XY = 93115.95, ∑X² = 320246.72
Thus, a = 22.909
and b = 0.209
Thus, Regression Line is given by,
y = 22.909 + 0.209 x
Thus, The course grade of a student in the course who spent an average of 103 minutes in the course each week is: 22.909 + 0.209 × 103 = 44.436
Now plotting these line:
Answer:
The Amount invested at 7% interest is $12,855
The Amount invested at 6% interest = $1,102
Step-by-step explanation:
Given as :
The Total money invested = $13,957
Let The money invested at 7% = = $A
And The money invested at 6% = = $13957 - $A
Let The interest earn at 7% =
And The interest earn at 6% =
-
= $833.73
Let The time period = 1 year
Now,<u> From Simple Interest method</u>
Simple Interest =
Or, =
Or, =
And
=
Or, =
∵ -
= $833.73
So, -
= $833.73
Or, 7 A - 6 (13,957 - A) = $833.73 × 100
Or, 7 A - $83,742 + 6 A = $83373
Or, 13 A = $83373 + $83742
Or, 13 A = $167,115
∴ A =
i.e A = $12,855
So, The Amount invested at 7% interest = A = $12,855
And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855
I.e The Amount invested at 6% interest = $1,102
Hence,The Amount invested at 7% interest is $12,855
And The Amount invested at 6% interest = $1,102 . Answer