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3 years ago

Which on is bigger 7/8 or 5/6

1 answer:

6 0

Nope - 7/8 is greater Here's a cool way to solve these types of problems First write 5/6ths and 7/8ths on a sheet of paper. Then multiply the numbers that are across from each other. 8x5 and 7x6 are the numbers. 8x5=40 7x6=42 42 is greater than 40, and the numerator of the fraction used in the equation is the bigger fraction. 7 is the numerator of 7/8 which is bigger than 5/6.

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The longest side of an acute triangle measures 30 inches. The two remaining sides are congruent, but their length is unknown.

Leno4ka [110]

Really, we don't need to use that much math--we can use logic instead. Since the two congruent sides must be longer than 30in, the total has to be greater than 60in (the longest side plus the congruent sides.) So for our answer, we want the smallest total that is above sixty, which in this case is 72.44in.

Hope I helped, and let me know if you have any questions :) I can explain the real math if you want, it was just unnecessary here.

3 0

4 years ago

Read 2 more answers

WILL MARK BRAINLIEST FOR BEST ANSWER! SERIOUS ANSWERS ONLY!

Veronika [31]

Answer:

$ 1850

Step-by-step explanation:

As it is simple interest, the interest will be same each year.

Interest = 2312.50 - 2081.25 = $ 231.25

The amount borrowed = 2081.25 - 231.25 = $ 1850

3 0

3 years ago

Nora invested $1,500 in a bond at a simple interest rate of 3%. How much will the bond be worth in total after 10 years?

attashe74 [19]

<h2>The bond will be worth in total after 10 years is =$1,950</h2>

Step-by-step explanation:

Given,

Nora invested $1,500 in at a bond simple interest rate of 3%

here P= $1500 R= 3% and t = 10year

Simple interest(I) = $\frac{P\times R \times t }{100}$

=$ $\frac{1500\times 3 \times 10}{100}$

=$ 450

<h3>The bond will be worth in total after 10 years is = $1,500+ $450</h3><h3> =$1,950</h3>

8 0

3 years ago

Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab

Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

$\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

<u>Right part:</u>

$\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}$

Since simplified left and right parts are the same, then the equality is true.

3 0

3 years ago

I just need #21 and #23 answered please.

kykrilka [37]

#21: Even
#23: Neither

7 0

3 years ago

Read 2 more answers