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marin [14]
3 years ago
11

Please help, easy geometry​

Mathematics
1 answer:
tester [92]3 years ago
8 0

Answer:

Step-by-step explanation:

There are a few ways to go about doing this problem. One method would to divide the shape into two triangles and a rectangle and then find the area of those shapes and then add them all up. I am not going to do that because that is the long way to solve this problem.

<u>With that said, you can use the trapezoid formula</u>

A = h*\frac{b1 + b2}{2}

b1 = 3

b2 = 11

h = 9

<u>Plugin the data into our model and do the math.</u>

A = h*\frac{b1 + b2}{2}

A = 9*\frac{3 + 11}{2}

A = 9*\frac{14}{2}

A = 9 * 7

A = 63 \ yd^2

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The drama club was selling tickets
Lubov Fominskaja [6]

Answer:

108 student tickets, and 176 adult tickets  were sold

Step-by-step explanation:

Adult ticket $8  Call the number of adult tickets sold "a"

Student ticket $5  Call the number of student tickets sold "s"

Since we are talking about TWO consecutive days of sold out seats, the total number of seats sold were 2* 142 = 284

Then we create two different equations with the information given:

a + s = 284

8 * a + 5 * s = 1948

we can solve for s in the first equation as follows: s = 284 - a

and use it in the second equation

8 a + 5 (284 - a) = 1948

8 a + 1420 - 5 a = 1948

combining

3 a = 528

a = 528/3

a = 176

we find the number of student tickets using this answer in the substitution equation we used:

s - 284 - 176 = 108

Therefore 108 student tickets, and 176 adult tickets  were sold.

5 0
2 years ago
What is 5✓28 +✓63 In simplest radical form<br>I need it asap.
Ksenya-84 [330]

Answer:

13✓7

Step-by-step explanation:

5✓28 + ✓63

Break the radical into perfect squares.


5 times ✓4 times ✓7  +  ✓9 times ✓7

5 times 2 times ✓7  +  3 ✓7


10✓7 + 3✓7


13✓7

5 0
3 years ago
Find x: 3/(x-4)(x-7) + 6/(x-7)(x-13) + 15/(x-13)(x-28) - 1/x-28 = -1/20
Novay_Z [31]

The value of x<em> </em>in the polynomial fraction 3/((x-4)•(x-7)) + 6/((x-7)•(x-13)) + 15/((x-13)•(x-28)) - 1/(x-28) = -1/20 is <em>x </em>= 24

<h3>How can the polynomial with fractions be simplified to find<em> </em><em>x</em>?</h3>

The given equation is presented as follows;

\frac{3}{(x - 4) \cdot (x - 7) }  + \frac{6}{(x - 7) \cdot (x - 13)   }  + +\frac{15}{(x - 13) \cdot (x - 28) } - \frac{1}{(x - 28)  } =  -  \frac{1}{20}

Factoring the common denominator, we have;

\frac{3\cdot(x - 13) \cdot(x - 28) + 6 \cdot(x - 4) \cdot(x - 28)  + 15 \cdot(x - 4) \cdot(x - 7)  - (x - 4) \cdot (x - 7)\cdot(x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)}   + =  -  \frac{1}{20}

Simplifying the numerator of the right hand side using a graphing calculator, we get;

By expanding and collecting, the terms of the numerator gives;

-(x³ - 48•x + 651•x - 2548)

Given that the terms of the numerator have several factors in common, we get;

-(x³ - 48•x + 651•x - 2548) = -(x-7)•(x-28)•(x-13)

Which gives;

\frac{-(x - 7) \cdot(x - 28)\cdot (x - 13)}{(x - 4) \cdot (x - 7)\cdot(x - 13) \cdot(x - 28)}   + =  -  \frac{1}{20}

Which gives;

\frac{-1}{(x - 4)}   + =  -  \frac{1}{20}

x - 4 = 20

Therefore;

  • x = 20 + 4 = 24

Learn more about polynomials with fractions here:

brainly.com/question/12262414

#SPJ1

5 0
1 year ago
15/35 in simplest form
Aleksandr-060686 [28]
Find the GCF of 15 and 35
15=3*5
35=7*5
The Greatest Common Factor here is 5
Divide both the numerator and denominator by this value to get the simplest form.
15/5=3
35/5=7
Final answer: 3/7
5 0
3 years ago
Read 2 more answers
Photo above need help
Ira Lisetskai [31]

Answer:

m = 0

Step-by-step explanation:

<u>If two lines are parallel, their slopes are equal. </u>

The slope of x - axis is 0

(why?)

because, slope of a line is given by

\boxed{\mathsf{slope\:of\:a\:line=tan \theta}}

Θ is the angle made by the line with the x- axis.

Here, the line in question is the x- axis itself, and every line makes an angle of 0° with itself.

=> Θ = 0

=> tan Θ = 0

=> slope = 0

and the line in blue is parallel to the X- axis, therefore, it's slope is also 0

(also, a line makes an angle of 0° with the line it's parallel to)

<u>                                </u>

\mathfrak{\overline{There\:You\:Are!}}

6 0
2 years ago
Read 2 more answers
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