Answer:
A. 0.9510
B. 0.0480
C. 0.0490
D. No, I would not feel comfortable accepting the shipment if one item was found defective, because the probability is quite small to obtain 1 or more defective items.
Answer:
x = 200
Step-by-step explanation:
Multiply by 4:
x + 120 + 2x = 720
3x = 600 . . . . . . collect terms, subtract 120
x = 200 . . . . . . . divide by 3
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<em>Check</em>
(200/4 +30) +(200/2) = 180
(50 +30) + 100 = 180
80 + 100 = 180 . . . . . true
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<em>Alternate solution</em>
If you like, you can simply work with the equation given.
(3/4)x + 30 = 180 . . . . collect terms
(3/4)x = 150 . . . . . . . . . subtract 30
x = 200 . . . . . . . . . . . . multiply by 4/3
Answer:
No Problem, I know That I personally can't stand it when people just give me the number. So another way to think of this problem is "How many 2/3 are in 3 cups." So try drawing 3 rectangles to represent 3 cups and then draw two lines inside those rectangles so that there are 3 rectangles inside each one and then shade in two of the smaller rectangles in a way that you can tell them all apart preferably different colors and then just count them.
Step-by-step explanation:
Hope this is enough to help you understand it, if not then feel free to ask for more info in the comments. :)
Answer:
a) 0.1558
b) 0.7983
c) 0.1478
Step-by-step explanation:
If we suppose that small aircraft arrive at the airport according to a <em>Poisson process</em> <em>at the rate of 5.5 per hour</em> and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:
(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?
(b) What is the probability that at least 4 arrive during a 1-hour period?
(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?
If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now
and we want <em>P(X ≥ 75) = 1-P(X<75)</em>. But
hence
P(X ≥ 75) = 1-0.852 = 0.1478
Answer:
26
Step-by-step explanation: