Find the number of units x that produces the minimum average cost per unit C in the given equation. C = 0.001x3 + 5x + 250
1 answer:
Answer:
50 units
Step-by-step explanation:
Find the number of units x that produces the minimum average cost per unit C in the given equation.
C = 0.001x³ + 5x + 250
unit cost f(x) = C/x
= 0.001x³/x + 5x/x+ 250/x
f(x) = 0.001x² + 5 + 250/x
f'(x) = 0.002x - 250/x²
We equate the first derivative to zero
0.002x - 250/x² = 0
0.002x = 250/x²
Cross Multiply
0.002x × x² = 250
0.002x³ = 250
x³ = 250/0.002
x³ = 125000
x = 3√(125000)
x = 50 units
Therefore, the number of units x that produces the minimum average cost per unit C is 50 units.
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On Monday, 11 lunches and 10 desserts are ordered. On Friday, 10 lunches and 10 desserts are ordered.
Answer:
t = 2.7
Step-by-step explanation:
1. Use formula provided
2. A = 3500 B = 2000 r = 4.75 n = 12months/4 = 3 months t = ?
3. Solve
3500=2000(1+4.75/3)^3t
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t ≅2.568
