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vladimir2022 [97]
3 years ago
6

help with number 2 please i have no idea how to do this. it would be very helpful if you can show the steps

Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0
So in this case, we have to replace the known value.
y=3
y=-2x+3

3=-2x+3

Then we leave our unknown value alone.
\frac{3-3}{2}= x

In this case, our x value would be 0.

We check it...
3=-2(0)+3
3=0+3
3=3

So y=3 x=0

For the second one we have...
y=3x+2
y=-3x-4

For this we substitute the y in any of the equation...
3x+2=-3x-4

We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2

Then we solve
6x=-6

Then we leave the unknown value alone.
x=\frac{-6}{6}

Then solve for x.
x= -1

Then for our y value we return to one of the original equations and substitute the x value.
y=3x+2
y=3(-1)+2
y=-3+2
y=-1

y=-3x-4
y=-3(-1)-4
y=3-4
y=-1

So in this case we got that x= -1 and y= -1
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Step-by-step explanation:

Question 1)

We have the function:

y=2(x+2)^2-3

Notice that this is a quadratic function in the vertex form:

y=a(x-h)^2+k

Where (h, k) is the vertex point, a is the leading co-efficient, and h is also the axis of symmetry.

Let's identify these characteristics first. Our leading co-efficient a is 2.

And our vertex is (-2, -3). It is <em>not</em> (2, -3) because (x+2) is the same as (x-(-2)).

We want to find the minimum or maximum value of our function, as well as the domain and range.

First, by looking at our leading co-efficient, which is 2, we can see that it's positive. Therefore, our parabola curves upwards.

Therefore, we will have a <em>minimum</em> value. And this minimum value will be our vertex.

Our vertex is (-2, -3). Therefore, our <em>minimum</em> value is at y=-3.

The domain of all quadratics is always all real numbers.

For the range, we refer to our minimum/maximum value.

Our parabola curves upwards and our <em>minimum </em>value is at y=-3.

Therefore, our range is all numbers <em>greater than or equal to </em>-3.

The choice that represents all of these answers is A.

Question 2)

We have:

y=2(x+2)^2-4

Again, this is in vertex form. Let's identify our characteristics.

Our leading co-efficient a is 2, so the graph curves upwards.

And our vertex is at (-2, -4).

The axis of symmetry is the same as the x-coordinate of our vertex. Therefore, our axis of symmetry is at x=-2.

So, this function has a vertex at (-2, -4) and an axis of symmetry at x=-2.

The choice that represents these characteristics is C.

So, our answer is C.

And we're done!

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