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4 years ago

help with number 2 please i have no idea how to do this. it would be very helpful if you can show the steps

Mathematics

1 answer:

zloy xaker [14]4 years ago

4 0

So in this case, we have to replace the known value.
y=3
y=-2x+3

3=-2x+3

Then we leave our unknown value alone.
$\frac{3-3}{2}$ = x

In this case, our x value would be 0.

We check it...
3=-2(0)+3
3=0+3
3=3

So y=3 x=0

For the second one we have...
y=3x+2
y=-3x-4

For this we substitute the y in any of the equation...
3x+2=-3x-4

We move the unknown values to one side and the ones without unlown values to the other side...
3x+3x=-4-2

Then we solve
6x=-6

Then we leave the unknown value alone.
x= $\frac{-6}{6}$

Then solve for x.
x= -1

Then for our y value we return to one of the original equations and substitute the x value.
y=3x+2
y=3(-1)+2
y=-3+2
y=-1

y=-3x-4
y=-3(-1)-4
y=3-4
y=-1

So in this case we got that x= -1 and y= -1

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Paul has an eight-year loan with a principal of $26,900. The loan has an interest rate of 8.18%, compounded quarterly. If Paul p

babymother [125]

Answer:

The answer is "option b"

Step-by-step explanation:

Amount = $26,900

r= 0.0818 %

$i=\frac{r}{4}\\\\$

$=\frac{0.0818}{4}\\\\=0.02045$

t= 8 years

$n= 8 \times 4$

$=32$

$D=\frac{1-(1+i)^{-n}}{i}\\$

$=\frac{1-(1+0.02045)^{-32}}{0.02045}\\\\=\frac{1-(1.02045)^{-32}}{0.02045}\\\\=\frac{1-0.52319627}{0.02045}\\\\=\frac{0.47680373}{0.02045}\\\\=23.3155858$

$Q= \frac{Amount}{Discount \ factor }\\$

$=\frac{26900}{23.3155858} \\\\=1153.73468$

Payment $=1153.73468 \times 32\\\\$

$= \$ 36919.5098\\$

$\text{Total interest = Payment - amount}$

$= \$ 36919.5098 - \$ 26900 \\\\ = \$ 10019.5098$

$\text{Finance charge = Total interest + service charge}$

$= \$ 10019.5098 + \$ 1527\\\\ = \$ 11546.5098$

3 0

3 years ago

The equation 4x2 – 24x + 4y2 + 72y = 76 is equivalent to

DerKrebs [107]

Answer:

Option 4 is correct.

The equation $4x^2 -24x + 4y^2 + 72y = 76$ is equivalent to $4(x-3)^2 + 4(y+9)^2 =436$

Step-by-step explanation:'

Given equation: $4x^2 -24x + 4y^2 + 72y = 76$

First group the terms with x and those with y;

$(4x^2-24x)+(4y^2+72y) = 76$

Next, we complete the squares.

We can do this by adding a third term such that the x terms and the y terms are perfect squares.

For this we must either add the same value on the other side of the equation or subtract the same value on the same side so that the equality is maintained.

⇒ $4(x^2-6x) +4(y+18y) = 76$