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postnew [5]
3 years ago
7

Can someone help me with these problems?

Mathematics
1 answer:
denis23 [38]3 years ago
8 0
I can number 1 is well I mean I’m learning this too but I suck at it so...sorry I can’t help but I can help with other stuff like social studies, science, and spelling
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Y= x^2 -5 solve for x
dexar [7]

Y= x^2 -5

We need to solve for x, we need to get x alone

Y= x^2 -5

Lets start by removing -5

Add 5 on both sides

y + 5= x^2 -5 + 5

y + 5= x^2

Now to isolate x , we need to remove the square from x

To remove square , take square root on both sides

+-\sqrt{y+5} = \sqrt{x^2}

square and square root will get cancelled

+-\sqrt{y+5} = x

So x = +\sqrt{y+5} and  x = -\sqrt{y+5}


7 0
3 years ago
Verify csc^2t-cos t sect= cot^2 t
Ymorist [56]

Rewriting the left hand side,

csc²t - cost sec t

= (1/sin²t)-(cost)(1/cost)

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= 1/sin²t - sin²t/sin²t

= (1-sin²t)/sin²t

= cos²t/sin²t

= cot²t

7 0
2 years ago
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marshall27 [118]

Answer:

c>16

Step-by-step explanation:

c-12>4

c> 4+12

c> 16

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3 years ago
8(c - 15)= -40 the solution is c =
erastovalidia [21]

Answer:

c = 10

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