Y equals 4x-2 that is my awnser
1) The domain is all the possible x values in the function so it would be [-4,4]
2) There are only 3 zeros shown on the graph and they are (-2, 0) (0, 0) (2, 0) the zeros are the value of x when y = 0.
3)The function is positive/Negative is asking for what x values make the y values positive aka interval notation. The function is positive if x = (0, 2) because 0 and 2 aren't included you use parentheses () instead of brackets []
The function is negative if x [-4, -2), (-2,0), (2,4]
The initial value is 3 (when x=0), and the multiplier is 2, when x=2. The equation can be written as
.. y = 3*(2^(x/2))
Answer:
no solution
Step-by-step explanation:
For getting the nature of solution of the quadratic equation of the form:
ax² + bx + c = 0
We need to find Discriminant which is:
Discriminant (D) = b² - 4ac
- If D < 0, there is no solution of equation.
- If D = 0, there are two equal and real solution of equation
- If D < 0, there are two real and distinct solution of equation
Here we have equation is:
2x² - 9x + 12 = 0
∴ a=2, b = -9, c = 12
⇒ D = 81 - 4 × 2 × 12 = -16 < 0
Hence, there is no solution of given equation.
