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vovikov84 [41]
3 years ago
15

List 3 values that would make the inequality true 48 < 6n

Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0

Answer: Three values of 'n' are 9, 10 and 11.

Step-by-step explanation:  We are given to list three values that would make the following inequality TRUE:

48

We have to find three values of the unknown quantity 'n' that that inequality (i) is true.

First, we have to solve the inequality (i).

The solution is as follows:

4848\\\\\Rightarrow n>\dfrac{48}{6}\\\\\Rightarrow n>8.

So, the three values of 'n' are 9, 10 and 11.

lutik1710 [3]3 years ago
6 0
The inequality:
48 < 6 n
6 n > 48
n > 48 : 6
n > 8
Answer: n = { 9, 10, 11 } ( 3 values )
We can prove this:  48 < 6*9  or 48 < 54,  48 < 60,  48 < 66
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tiny-mole [99]

Answer:

30 years: 1.38

45 years: 2.07

65 years:2.99

Step-by-step explanation:

$1x0.046=0.046

0.046x30=1.38

0.046x45=2.07

0.046x65=2.99

this is assuming that it gets interest yearly and that they don't want the original amount included.

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3 years ago
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What number am I
laiz [17]

Answer:

21

Step-by-step explanation:

So, factors of 6 that are between 17 and 25 are 18 and 20, so that's not the numbers.

Multiples of 3 are 18, 21, and 24.

The only number that would be reasonable enough is 21, because it is a multiple of 3 and is not a factor of 6.

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3 years ago
What is the solution to 6x + 1 = 4x -3
PSYCHO15rus [73]

6x +1 = 4x -3

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What’s the slop it’s on my final
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The slope is 1

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En la preparación de un perfume se cuenta con dos tipos de esencia base: 1600 ml de una y 1680 ml de otra. Se quiere envasarlas,
Lostsunrise [7]

Answer:

33,600 frascos

Step-by-step explanation:

Resolvemos esta pregunta utilizando el método mínimo común múltiple

Encuentre y enumere los múltiplos de 1600 y 1680 hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

Múltiplos de 1600:

1600, 3200, 4800, 6400, 8000, 9600, 11200, 12800, 14400, 16000, 17600, 19200, 20800, 22400, 24000, 25600, 27200, 28800, 30400, 32000, 33600, 35200, 36800

Múltiplos de 1680:

1680, 3360, 5040, 6720, 8400, 10080, 11760, 13440, 15120, 16800, 18480, 20160, 21840, 23520, 25200, 26880, 28560, 30240, 31920, 33600, 35280, 36960

Por lo tanto,

LCM (1600, 1680) = 33,600

La menor cantidad de frascos necesarios es 33,600 frascos.

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