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BlackZzzverrR [31]
3 years ago
7

I need help on 11,13,14,15

Mathematics
1 answer:
vlabodo [156]3 years ago
6 0
Use photomath... but i already did 11 and its -52
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Is the given sequence arithmetic? If so, identify the common difference. 3.2, 3.5, 3.8, 4.1, . . .
sweet [91]
3.5 - 3.2 = 3.8 - 3.5 = 4.1 - 3.8 = 0.3 (common difference)
3 0
3 years ago
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A special liquid is held in a tank described as (x 2 + y 2 ) ≤ z ≤ 1 in a Cartesian coordinate system. Assume that the density o
vivado [14]

Since \rho=\dfrac mV (density = mass/volume), we can get the mass/weight of the liquid by integrating the density \rho(x,y,z) over the interior of the tank. This is done with the integral

\displaystyle\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{x^2+y^2}^1(2-z^2)\,\mathrm dz\,\mathrm dy\,\mathrm dx

which is more readily computed in cylindrical coordinates as

\displaystyle\int_0^{2\pi}\int_0^1\int_{r^2}^1(2-z^2)r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\boxed{\frac{3\pi}4}

7 0
3 years ago
Which linear inequality is represented by the graph?
Tamiku [17]

Answer:

Option (4)

Step-by-step explanation:

From the graph attached,

A dotted line passes through two points (3, 1) and (-3, -3)

Let the equation of the given line is,

y = mx + b

where 'm' = slope of the line

b = y-intercept

Slope of a line passing through (x_1, y_1) and (x_2,y_2) is,

m = \frac{y_2-y_1}{x_2-x_1}

For the given points,

m = \frac{1+3}{3+3}

m = \frac{2}{3}

y-intercept 'b' = -1

Therefore, equation of the given line will be,

y=\frac{2}{3}x-1

Since graphed line is a dotted line so it's representing an inequality(having < or > sign)

And the shaded part is below the dotted line,

Inequality will be,

y < \frac{2}{3}x-1

Therefore, Option (4) will be the answer.

7 0
3 years ago
If the area of a triangle is 36 in.^2in.
disa [49]
C. 8 inches. I hope I'm not too late
4 0
3 years ago
I need help on both of these please///:(
SCORPION-xisa [38]

14. The distance between the two points is 14.866.

Distance can be calculated with the following formula:

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(12-2)²+(5-(-6))²

d=√10²+11²

d=√100+121

d=√221

d=14.866

15. The distance between the two points is 20.248.

Use the same formula to find the distance.

d=√(x₂-x₁)²+(y₂-y₁)²

d=√(4-(-3))²+(12-(-7))²

d=√7²+19²

d=√49+361

d=√410

d=20.248

4 0
3 years ago
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