Answer: There are 18 elements in the sample space for this experiment
Step-by-step explanation:
Total cards = 52
Total outcomes on tossing a coin = 2 [1 head , 1 tail]
If the card is a club, a fair coin is flipped 9 times and the number of heads flipped is noted (but card drawn is not noted)).
Possible outcomes for heads = 0,1,2,...,9
So sample space for this event = {0,1,2,3,4,5,6,7,8,9} <em> </em><em> (Total </em><em>10 elements</em><em> ) </em><em> (i)</em>
If it is not a club, the coin is only flipped 3 times, but this time the result of each flip is noted(but card drawn is not noted).
Sample space with all possible outcomes ={TTT,TTH, THT, HTT, HTH,HHT,THH,HHH} <em> (Total </em><em>18 elements</em><em> ) </em><em>(ii)</em>
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From (i) and (ii), Total elements in the sample space for this experiment = 10+8 = 18
Hence, there are 18 elements in the sample space for this experiment
