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tigry1 [53]
3 years ago
7

The ages of three children in a family can be expressed as consecutive integers. The square of the age of the youngest child is

4 more than 8 times the age of the oldest child. Find the ages of the three children.
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0

Answer: 10, 11, & 12

<u>Step-by-step explanation:</u>

Let x represent the age of the youngest child.  

Their ages are consecutive so,

Youngest: x

Middle: x + 1

Oldest: x + 2

The age of the Youngest squared (x²) equals 8 times the Oldest [8(x + 2)] plus 4.

x² = 8(x + 2) + 4

x² = 8x + 16 + 4

x² = 8x + 20

x² - 8x - 20 = 0

(x - 10)(x + 2) = 0

x - 10 = 0     or      x + 2 = 0

  x = 10       or          x = -2

Since age cannot be negative, x = -2 is not valid

So, the Youngest (x) is 10

the Middle (x + 1) is 11

and the Oldest (x + 2) is 12

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