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2 years ago

8

Art and his friends spent $62 at the movies. Admission tickets cost $12 apiece, and a bucket of popcorn costs $7. Which equation

written in standard form represents the number of tickets bought, t, and the number of buckets of popcorn bought, p?

1 answer:

Darya [45]2 years ago

8 0

Answer: 12t+7p=62

Step-by-step explanation:

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A survey of 100 similar-sized hospitals revealed a mean daily census in the pediatrics service of 27 with a standard deviation o

Vinil7 [7]

Answer:

We conclude that the mean is greater than 25.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 25

Sample mean, $\bar{x}$ = 27

Sample size, n = 100

Alpha, α = 0.05

Sample standard deviation, s = 6.5

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 25\\H_A: \mu> 25$

We use One-tailed(right) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{27 - 25}{\frac{6.5}{\sqrt{100}} } = 3.07$

Now, $z_{critical} \text{ at 0.05 level of significance } = 1.645$

Since,

$z_{stat} > z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis.

Thus, the mean is greater than 25.

3 0

2 years ago

Please help and explain!!!!!

FinnZ [79.3K]

Let $x$ be the amount of the 30% alloy and $y$ the amount of the 60% alloy the metalworker will use. However much is used, the final alloy will have a mass of

$x+y=100$

kilograms. For each kg of the 30% alloy used, 0.3 kg is copper; similary, each kg of the 60% alloy contributes 0.6 kg, so that

$0.3x+0.6y=0.54(x+y)=54$

Now,

$x+y=100\implies y=100-x$

$\implies0.3x+0.6(100-x)=54$

$\implies60-0.3x=54$

$\implies0.3x=6$

$\implies x=20$

$\implies y=100-20=80$

6 0

3 years ago

PLS HELP ME 6, 7, and 8 (SHOW WORK!!) + LOTS OF POINTS + THANKS! + BRAINLIEST IF POSSIBLE!

julsineya [31]

6. $1 \frac{1}{2} = \frac{6}{4}$ since $\frac{1}{4} = 4$ feet. Then 6*4=24 So the answer is C

7. 1200 m/8 cm = C. 1 cm = 150 m

8. A. Since 1 in = 3 feet then 6 inches = 18 feet (6*3=18) and 4 inches = 12 feet (4*3=12) so the dimensions of her room are 16'x12'.

B. A=lxw so 16*12= 216 $m^{2}$

Hope that helps

6 0

2 years ago

Read 2 more answers

A cone has a height of 4 in and a radius of 6 in. What is the volume of the cone?

MatroZZZ [7]

Answer:

48π in³

Step-by-step explanation:

$V=\frac{1}{3} \pi r^2h$

Plug in the radius 6 in and the height 4 in

$V=\frac{1}{3} \pi (6)^2(4)\\V=\frac{1}{3} \pi (36)(4)\\V=\frac{1}{3} \pi (144)\\V=48\pi$

Therefore, the volume of the cone is 48π in³.

I hope this helps!

3 0

2 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$

$$+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}$

Let us solve the term one by one.

$$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}$

$$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y$

$$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}$

$$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}$

$$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}$

$$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}$

Substitute these into the above expansion.

$(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}$

The coefficient of $x^{2} y^{3}$ is 40.

Option C is the correct answer.

5 0

2 years ago