La figura MNPQ es un rombo. Si 2θ – Φ =60°. Calcula el valor de “x”. Dime los fundamentos y principios que utilizas.
1 answer:
Answer:
x = 30°
Step-by-step explanation:
Donde 2θ - Φ = 60 °, tenemos;
∠QMN = ∠QPM
Ф + ∠P / 2 + (180 - θ) = 180 (Suma de ángulos en un triángulo ΔQLP)
Por lo tanto, Ф + ∠P / 2 - θ = 0
Por lo tanto, ∠P / 2 = θ - Ф, también
270 ° + θ + x + ∠P / 2 = 360 (Suma de ángulos en un NOLP cuadrilátero) da
270 ° + θ + x + θ - Ф = 270 ° + 2 · θ - Ф + x = 360
Como 2 · θ - Ф = 60 °, tenemos;
270 ° + 60 + x = 360
x = 360 - 270 - 60 = 30 °
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