La figura MNPQ es un rombo. Si 2θ – Φ =60°. Calcula el valor de “x”. Dime los fundamentos y principios que utilizas.
1 answer:
Answer:
x = 30°
Step-by-step explanation:
Donde 2θ - Φ = 60 °, tenemos;
∠QMN = ∠QPM
Ф + ∠P / 2 + (180 - θ) = 180 (Suma de ángulos en un triángulo ΔQLP)
Por lo tanto, Ф + ∠P / 2 - θ = 0
Por lo tanto, ∠P / 2 = θ - Ф, también
270 ° + θ + x + ∠P / 2 = 360 (Suma de ángulos en un NOLP cuadrilátero) da
270 ° + θ + x + θ - Ф = 270 ° + 2 · θ - Ф + x = 360
Como 2 · θ - Ф = 60 °, tenemos;
270 ° + 60 + x = 360
x = 360 - 270 - 60 = 30 °
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Answer:
The distance of the point from the origin = 9.29 units.
Step-by-step explanation:
Given point:
(7,-6)
The angle lies such that the terminal side of the angle contains the given point.
To draw the angle and find the distance from the origin to the given point.
Solution:
The terminal side of the angle is where the angle ends with the initial side being the positive side of the x-axis.
So, we can plot the point (7,-6) by moving 7 units on the x-axis horizontally and -6 units on the y-axis vertically.
We can find the distance of the point from the origin by find the hypotenuse of the triangle formed.
Applying Pythagorean theorem.
Taking square root both sides :
Thus, the distance of the point from the origin = 9.29 units.
The figure is shown below.
Answer:
27 days
Step-by-step explanation:
20 ÷
= 27