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3 years ago

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Please Hurry!!!!

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skelet666 [1.2K]3 years ago

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A radio station gave away concert tickets every hour yesterday. At the end of the fifth hour, the station had 418 tickets left.

zaharov [31]

-22x+y=415

I think that this is the answer

3 0

3 years ago

Please need help asap!!

vagabundo [1.1K]

$a+b+c=180, \text{ }c+e=180 \implies \\ a+b+c=c+e \implies \\ a+b=e\\$

This result is actually true for any exterior angle. The exterior angle of a triangle is equal to the sum of the two remote angles, and above is a short proof of it.

6 0

3 years ago

which answer choice explains the pattern for how to find the slope using an equation in standard form?

Liono4ka [1.6K]

Question is using standard formula ax+by=c to find the slope by converting into slope intercept form y=mx+b

so we also need to convert ax+by=c into y=mx+b as shown below:

$ax+by=c$

$ax+by-ax=c-ax$

$by=-ax+c$

divide both sides by

$y=-\frac{a}{b}x+\frac{c}{b}$

Now compare it with y=mx+b, we get

$m=-\frac{a}{b}$

So using values of a and b, we can find the slope

compare given equation -5x+2y=15 with ax+by=c, we get:

a=-5, b=2

Now plug both into above formula

$m=-\frac{a}{b}$

$m=-\frac{-5}{2}$

$m=\frac{5}{2}$

Now matching these details with given choices we find that THIRD choice is the final answer.

7 0

3 years ago

Write a equivalent expression for 12a+60

viva [34]

Answer: 12(a+5)

Step-by-step explanation: factor out 12 from the expression

ANSWER 12(a+5)

8 0

3 years ago

If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e

Pepsi [2]

The outlier of a dataset is a data element that is relatively far from the remaining data elements

<em>99 is an outlier of pet group</em>
<em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

$n = 15$

The quartiles positions are:

$Q_1 = \frac{n + 1}{4}$

$Q_1 = \frac{15 + 1}{4}$

$Q_1 = \frac{16}{4}$

$Q_1 = 4th$

$Q_3 = Q_1 \times 3$

$Q_3 = 4th \times 3$

$Q_3 = 12th$

So, we have:

$Q_1 = 4th$

$Q_3 = 12th$

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

$Q_1 = 68$

$Q_3= 79$

The lower and upper limits of the outlier are:

$L = Q_1 - 1.5 \times (Q_3 - Q_1)$

$U = Q_3 + 1.5 \times (Q_3 - Q_1)$

So, we have:

$L = 68 - 1.5 \times (79 - 68)$

$L = 51.5$

$U = 79+ 1.5 \times (79 - 68)$

$U = 95.5$

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

5 0

3 years ago