<u> case a)</u> The area of the square hole is 8 square centimeters
we know that
the area of a square is equal to

where
b is the length side of the square
in this problem we have

<u>Find the length side b</u>

<u>the answer Part a) is</u>
the length side of the square is 
Part b) The volume of a cube shaped block is 64 cubic centimeters
we know that
the volume of a cube is equal to

where
b is the length side of the cube
in this problem we have

<u>Find the length side b</u>
![b^{3} = 64 \\b= \sqrt[3]{64} \\b= 4\ cm](https://tex.z-dn.net/?f=b%5E%7B3%7D%20%3D%2064%20%5C%5Cb%3D%20%5Csqrt%5B3%5D%7B64%7D%20%5C%5Cb%3D%204%5C%20cm)
therefore
<u>the answer Part b) is</u>
the length side of the cube is 
In order to calculate the equivalent discount, consider the principle number is 100,
Then, 100 - 100 * 0.20 = 100 - 20 = 80
Now, 80 - 80 * 0.15 = 80 - 12 = 68
So, Total discount would be: 100 - 68 = 32%
Hope this helps!
You should probably define what makes a car "nice", and also quantify the "too much money".
Qualitative words are often not welcomed in maths/science in general, because people can disagree on their meaning.
So, for example, if you change the sentence into
"A report states that 32% of New Jersey residents think that mercedes cars cost 30% more than they should"
Then everything would be "fixed", and there is no ambiguity anymore
Answer:
s=4
Step-by-step explanation:
area of square is side*side
so that means s*s=16
so s = 4
Answer:
Area of square pyramid is
.
Step-by-step explanation:
Diagram of the given scenario is shown below,
Given that,
The Great Pyramid in Giza, Egypt is a square pyramid. The area of base shape is made up with square is
. The side of the square is
and The height of each triangle is
.
So, Area of Square shape = 
Side of square = 
Height of each triangle = 
Finding the Height of triangular shape which is here known as slant height.
In Δ ABO, applying Right angle pythagorean Theorem,
Base
= 
Height
= 
Now,
∴ 
⇒ 
⇒ 
⇒ 
⇒ 
Then,
Area of square pyramid = 
=
= 
= 
= 
Hence, Area of square pyramid is
.