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Gennadij [26K]
2 years ago
13

The ratio between the square of a number and it's cube is 1:3 what is the number ​

Mathematics
1 answer:
Dimas [21]2 years ago
4 0

Answer:

3

Step-by-step explanation:

Call that number “x”

The square of that number is x^2

Also as the cube is x^3

The ratio between these 2 values is 1:3, this means x^2 / x^3 = 1 / 3

<==> 1 / x = 1 / 3 (eliminate “x^2” for numerator and denominator of the fraction x^2 / x^3 )

<==> x = 1 * 3 / 1 = 3

So, that number is 3 ! This math problem seems simple ;)

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If (-5x^5) (a) = 25x^7 + 100x^5, find a
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(-5x^5)(a) = 25x^7 + 100x^5
<u>+5x^5                         +5x^5</u>
             a = 25x^7

4 0
2 years ago
Suppose the average math SAT score for students enrolled at local community college is 490.4 with a standard deviation of 63.7.
lakkis [162]

Answer:

Option B) 9.1      

Step-by-step explanation:

We are given the following in the question:

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Standard deviation = 63.7

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=\dfrac{\sigma}{\sqrt{n}}

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8 0
2 years ago
Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t
hram777 [196]

Answer:

a.\mu=15

b.\mu=7.8586 \ and  \ \mu=22.1414

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

P(X=k)=C_k^n.p^k.(1-p)^{n-k}

Let n be the number of trials,n=100

and p be the probability of success,p=15\%

The mean of a binomial distribution is the probability x sample size.

\mu=np=100\times0.15=15

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as:\sigma=\sqrt npq\\q=1-p

Therefore, \sigma=\sqrt(100\times0.015\times0.85)=3.5707

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c.  x=45 is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

4 0
3 years ago
Another brainliest if its right
tekilochka [14]

Answer:

16 : 14 = 30 : 26.25

Step-by-step explanation:

If rounded:

16 : 14 = 30 : 26

8 0
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I am pretty sure x=2
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