<em>Two </em>or <u>more</u> triangles are said to be congruent if and only if they have <u>equal</u> lengths of <em>sides</em> and <u>equal</u> measures of <em>angles</em>.
Thus, the required <u>proof</u> is as shown below:
<u>STATEMENTS </u> <u>REASONS</u>
1. ΔABC and ΔDEC with AB ≅ DE;
BC ≅ EC; <1 ≅ <2 Given
2. <1 and < ABC; < 2 and <DEC are sup <u>Sum</u> of angles on a <em>straight </em>line
3. <ABC ≅ <DEC <em>Congruent</em> angles of <u>similar</u> triangles
4. ∴ΔABC ≅ ΔDEC <em>Side-Angle-Side</em> (SAS) postulate
5. ∴<ACB ≅ <DCE CPCTC postulate
For more clarifications on the properties of congruent triangles, visit: brainly.com/question/1675117
#SPJ1
Answer:
5400
Step-by-step explanation:
9 seconds
F(t)=0
0= -16t^2+144t
Than solve for “t”
t=0 or t=9
And 0 seconds doesn’t make sense so it is 9 seconds
step-by-step explanation:
#1: simplify both sides of the equation.
2(x+3)−4x=x
(2)(x)+(2)(3)+−4x=x
2x+6+−4x=x
(2x+−4x)+(6)=x
−2x+6=x
−2x+6=x
***
#2: subtract x from both sides.
−2x+6−x=x−x
−3x+6=0
***
#3: subtract 6 from both sides.
−3x+6−6=0−6
−3x=−6
***
step 4: divide both sides by -3.
−3x/-3 = -6/-3
solution x = 2
