The solution would be x=0 because the statement is false.
3 is the remainder because the closest is 7 times 21 so it’s remainder 3
Answer:
0.0012
Step-by-step explanation:
0.0096/8=0.0012
No, a cubic equation can not have three complex roots. This is because it turns twice and one end goes to positive infinity and one end goes to negative infinity. Thus, one of these MUST cross the x-axis at some point, meaning y = 0 and a real root exists.
Yes, a cubic equation can have three real roots if it cuts the x-axis three times.
