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yuradex [85]
2 years ago
10

In an experiment, the enzyme lactase is added to milk in a test tube. The products obtained are glucose and galactose. Which of

these CORRECTLY explains the function of the enzyme in this reaction?
A) The enzyme molecules collide with the substrate and break it into simpler products.

B) The enzyme has active sites where the substrate binds with the enzyme to form a complex.
Eliminate

C) The substrate binds at the non-active sites of the enzyme, where it is broken down into simpler compounds.

D) The substrate breaks the bonds of the enzyme, resulting in the formation of simpler products.
Biology
2 answers:
vampirchik [111]2 years ago
8 0

The correct answer is option B) The enzyme has active sites where the substrate binds with the enzyme to form a complex.

The active site of the enzyme is the location, where the substrate bind to it. The binding of the substrate with the enzyme result in the formation of the enzyme substrate complex. After this, the substrate is converted into the products. The lactose is a disaccharide, which have glucose and the galactose monomer. Lactase is an enzyme, which help in the lysis of the lactose in glucose and galactose.

stich3 [128]2 years ago
4 0
B) The enzyme has active sites where the substrate binds with the enzyme to form a complex. When the substrate binds to the active site, an induced fit is formed where the enzyme changes its shape in order to better serve the substrate and lower the activation energy of the reaction.
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The students concluded that pea plants grew better in compost than did melon plants. Which of the following best addresses the v
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c. The conclusion is invalid because other variables in the experiment affected the results.

Explanation:

Consider the complete problem:

A group of students designed an experiment to determine the effect of compost on the germination and growth of plants.

The students set up experimental plots by mixing different ratios of soil and compost. They planted 20 pea and 20 melon

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plants grew they recorded the plant length, number and size of leaves, and general health observations.

The following observations were recorded.

 In all treatments, more pea seeds germinated than melon seeds

 There was a week of rainy weather at 3 weeks

 Melon plants developed a fungal growth at four weeks

 Melon plants grew longer than pea plants, but many melon leaves showed signs of yellowing as the weeks passed

The students concluded that pea plants grew better in compost than did melon plants. Which of the following best

addresses the validity of the conclusion made by the students?

a. The conclusion is valid because the independent and dependent variables in the experiment were controlled.

b. The conclusion is valid because the experimental design included a large sample size.

c. The conclusion is invalid because other variables in the experiment affected the results.

d. The conclusion is invalid because the units of measurement were not given in the experimental design.

<em>In order for the conclusion to be valid, all the independent variables should have been controlled. In this case, the independent variables such as the amount of water received by the plants, nutrient requirement of the plants, etc. were not controlled leading to fungal attack on the melon plant.</em>

<em>Hence, the conclusion is invalid because other variables that ought to have been controlled affected the experimental outcome.</em>

<em>The correct option is c.</em>

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3 years ago
The third step is the phosphorylation of fructose-6-phosphate, catalyzed by the enzyme phosphofructokinase. A second ATP molecul
algol13

Answer:

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Explanation:

It is used when a product of the reaction is used for regulate the reaction. Therefore when there is enough product like ATP in this situtation, there is no need to run the reaction.

4 0
3 years ago
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