Answer:
If both parents do not have sickle-cell anemia, than the possibility is low.
Explanation:
If both parents have the sickle-cell trait, their offspring has a 25 percent chance of getting sickle cell anemia and a 50 percent risk of them having sickle cell trait. Meanwhile, there is also a 25 percent chance of the child not getting it at all.
If one parent has sickle cell anemia and the other has sickle cell trait, then their offspring with have a 50 percent chance of getting sickle cell anemia and a 50 percent chance of getting a sickle cell trait.
When both parents have sickle cell anemia, their child will definitely have it.
Answer:
a) False.
b) True.
c) False.
d) True.
e) False.
f) True
g) True.
Explanation:
a) The main characteristic of homologous chromosomes is that they have an equal size. There is a difference in size on both chromosomes.
b) In number one, two chromosomes are homologous. In number two also two chromosomes are homologous. On the other hand, the chromosomes at number one and two are different. Each chromosome has two sister chromatids.
c) A DNA molecule has a double helix, that is, two chains. When a DNA chain is broken and a chromatide has a DNA chain, then two chromatids make up a chromosome and a DNA chain, in this way there are eight dsDNA molecules
d) If each chromosome contains a centromere, therefore, there are four centromeres on all four chromosomes.
e) If a chromosome contains four telomeres, therefore there will be sixteen telomeres.
f) The function of cohesin is to regulate the separation of chromatids in the cell division process. When DNA replication is complete, the DNA compacts and condenses to form mitotic chromosomes.
g) The CENPA protein is encoded by the CENPA gene.
C. It happens over a period of time not overnight
d.<span>29,035 feet mount eversest</span>
Transverse waves contain crests & troughs
while longitudinal waves contains compressions &rarefactions.
Answer and Explanation:
<u>Cross:</u> aa Bb dd Ee x AA bb Dd Ee
We can calculate the probability of getting heterozygous individuals in the progeny by using the <u>product rule</u>. Assuming that these four genes <u>assort independently</u> (<em>events that occur independently from each other</em>), we can infer that the F1 will have the next genotypic proportions for each gene:
1) aa x AA
F1) 4/4=1 Aa
2) Bb x bb
F1) ½ bb
½ Bb
3) dd x Dd
F1) ½ dd
½ Dd
4) Ee x Ee
F1) ¼ EE
2/4 = ½ Ee
¼ ee
So, to know what the probability is that the F1 of being heterozygous for all loci, we must multiply the respective individual probabilities of getting a heterozygous genotype, like this:
1 Aa x ½ Bb x ½ Dd x ½ Ee = 1/8 AaBbDdEe
