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Lyrx [107]
3 years ago
14

The observatory in the John Hancock Center in Chicago is located in the top floor, 900 feet above the ground. The express elevat

or travels nonstop from the ground floor to the observatory on the top floor at a rate represented by the equation y=30x, where y is the height, in feet, and x is the number of seconds.
Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

Step-by-step explanation:

Given the rate at which the elevator travels modeled by the expression;

y = 30x where y is the height, in feet, and x is the number of seconds.

If the observatory in the John Hancock Center in Chicago is located in the top floor, 900 feet above the ground, we can calculate the time taken to reach the top floor by substituting y = 900 into the equation and solve for x as shown;

y = 30x

900 = 30x

Rearrange

30x = 900

Divide both sides by 30

30x/30 = 900/30

x = 30

Hence it takes 30seconds for the elevator to reach the top floor

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3x + 2y = 5 5x + 2y = 7 Based on the given system of equations, which of the following is not true? 2x = 2 8x = 12 4y = 4
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<h3>Answer:</h3>

8x = 12

<h3>Explanation:</h3>

Subtracting the first equation from the second, you get ...

... (5x +2y) -(3x +2y) = (7) -(5)

... 2x = 2 . . . . . the first answer choice is true

___

Multiplying this expression for x by 4, we get

... 8x = 8 . . . . . the second answer choice (8x=12) is false

___

Adding thee first equation to the second, you get ...

... (3x +2y) +(5x +2y) = (5) +(7)

... 8x +4y = 12

... 8 + 4y = 12 . . . . . . use the value of 8x just computed

... 4y = 4 . . . . . . . . . . subtract 8; the third answer choice is true

_____

<em>Alternate approaches</em>

In short, if you solve the system by any of the methods available, you find x=1 and y=1, so the second answer choice is clearly the correct one:

... 8x ≠ 12

By Cramer's method:

... x = (2·7-2·5)/(2·5-2·3) = 4/4 = 1

... y = (5·5-7·3)/4 = 4/4 = 1

By graphing, see attached.

By substitution (for 2y):

... 5x +(5-3x) =7 . . . . . using 2y=5-3x

... 2x = 2 . . . . . . subtract 5

... x = 1 . . . . . . . .divide by 2

... 5 -3·1 = 2y = 2 . . . . substitute x into the expression for 2y

... y = 1 . . . . . . . divide by 2

By matrix methods, see the second attachment. (x, y) = (1, 1), found in the rightmost column of the result.

6 0
4 years ago
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