All categories

3 years ago

A man is four times as old as his son. In 3 years time, the father will be three times as old as the son. How old is each now?

2 answers:

5 0

The father is 24 years old and the son is 6 years old. You know this is right because it shows that the father 4 times older than the son

dem82 [27]3 years ago

4 0

The father is 27 because when they said 3 TIMES OLDER THEN THE SON he was 9

You might be interested in

I still can’t figure out this stupid simple interest question! I tried several answer n NONE worked so I’m gonna try 1 last time

natka813 [3]

t = $\frac{I}{Pr}$

isolate t by dividing both sides by Pr

$\frac{I}{Pr}$ = t ⇒ t = $\frac{I}{Pr}$

7 0

3 years ago

The cost, £C, of hiring a lorry to travel n miles is given by

zysi [14]

Part A:
C= a + bn

Make the two equations out of the words:
82 = a + b100 * 2.5 = 205 = a + b250
157 = a+ b250

Subtract the two,
205 = a + b250
- ( 157 = a + b250)
48 = a

Find b by substituting in a:
82 = a + b100
82 = 48 + b100
34 = b100
b = 0.34
Answer for part a: a = 48 , b = 0.34

Part B:
C = a +bn <- when n = 300 , put in a and b, then solve
C = 48 + 0.34(300)
C = 48 + 102
C = 150

Cost when hiring a lorry to travel 300 miles is 150 pounds

7 0

3 years ago

Read 2 more answers

4) Get Fit Headquarters charges $40 per month and $3 per exercise class. Fit Planet

Allisa [31]

Answer:

After 4 exercise classes, the monthly cost will be the same at each gym

The cost will be $52

Step-by-step explanation:

Assume that the number of the exercise classes is x

∵ Get Fit Headquarters charges $40 per month and $3 per exercise class

∵ The number of the exercise classes is x

→ Add $40 to the product of x and $3 to get the monthly cost

∴ The monthly cost of Get Fit = 3x + 40

∵ Fit Planet charges $20 per month and $8 per exercise class

∵ The number of the exercise classes is x

→ Add $20 to the product of x and $8 to get the monthly cost

∴ The monthly cost of Fit Planet = 8x + 20

∵ They have the same monthly cost

→ Equate their monthly cost to find x

∴ 8x + 20 = 3x + 40

→ Subtract 3x from both sides

∵ 8x - 3x + 20 = 3x - 3x + 40

∴ 5x + 20 = 40

→ Subtract 20 from both sides

∵ 5x + 20 - 20 = 40 - 20

∴ 5x = 20

→ Divide both sides by 5

∴ x = 4

∵ x is the number of the exercise classes

∴ After 4 exercise classes the monthly cost will be the same at each gym

→ Substitute the value of x in one of the monthly cost to get it

∵ The monthly cost of the Get Fit = 3(4) + 40

∴ The monthly cost of the Get Fit = 12 +40

∴ The monthly cost of the Get Fit = 52

∴ The cost will be $52

6 0

3 years ago

Is it true that the integral LaTeX: \int x^2e^{2x}dx ∫ x 2 e 2 x d x can be evaluated using integration by parts? If so, state t

Marysya12 [62]

Answer:

Yes the integral can be evaluated by integration by parts as solved below.

Step-by-step explanation:

$\int x^{2}e^{2x}dx$

Taking algebraic function as first function and exponential function as second function we have

$\int x^{2}e^{2x}dx=x^{2}\int e^{2x}dx-\int (x^{2})'\int e^{2x}dx\\\\=x^{2}\frac{e^{2x}}{2}-\int 2x\times \frac{e^{2x}}{2}dx\\\\\frac{x^{2}e^{2x}}{2}-\int xe^{2x}dx\\\\Now\\\\\int xe^{2x}dx=x\int e^{2x}dx-\int 1\cdot \int e^{2x}dx\\\\=\frac{xe^{2x}}{2}-\int \frac{e^{2x}}{2}dx\\\\\frac{xe^{2x}}{2}-\frac{e^{2x}}{4}\\\\\therefore \int x^{2}e^{2x}dx=\frac{x^{2}e^{2x}}{2}-\frac{xe^{2x}}{2}+\frac{e^{2x}}{4}$

5 0

3 years ago

Can somebody please help me

Alja [10]

Answer:

EH = 16

Perimeter = 46

Step-by-step explanation:

We see that the ratio between the big shape and small shape is 3:2. 3x=24, so x=8. EH=2x=16.

For the second problem, the perimeter is 46.

This is because it also follows the same rule as 3:2. If you do this for every side, you find out that the sides are 10, 10, 6, 12, and 8. Add them together to get 46.

I hope this helped!

It would be greatly appreciated if you marked this answer as brainliest!

4 0

2 years ago