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Anna35 [415]
3 years ago
6

What is the common difference of the following arithmetic sequence? 120, 108, 96, 84, ...

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

-12

Step-by-step explanation:

120-108 = -12

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Which shows a difference of squares?
d1i1m1o1n [39]

Answer:

The equations shows a difference of squares are:

<u>10y²- 4x²</u>   $   <u>6y²- x²</u>

Step-by-step explanation:

the difference of two squares is a squared number subtracted from another squared number, it has the general from Ax² - By²

We will check the options to find which shows a difference of squares.

1) 10y²- 4x²

The expression is similar to the general form, so the equation represents a difference of squares.

It can be factored as (√10 y + 2x )( √10 y - 2x)

2) 6y²- x²

The expression is similar to the general form, so the equation represents a difference of squares.

It can be factored as (√6y + x )( √6y - x)

3) 8x²−40x+25

The expression is not similar to the general form, so the equation does not represent a difference of squares.

4) 64x²-48x+9

The expression is not similar to the general form, so the equation does not represent a difference of squares.

6 0
3 years ago
Can anybody helppp meee please
crimeas [40]

Answer:

r^2=(A/pi)

Step-by-step explanation:

if A=pi*r^2 then maybe dividing by pi to get r^2 alone says r^2=(A/pi) or to get rid of the exponent you may square root each side so r=(sqrt(A/pi))

3 0
3 years ago
Help asappppp<br> please
Juli2301 [7.4K]

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely.

<h3>What is the equation of a line?</h3>

A line is a one-dimensional shape that is straight, has no thickness, and extends in both directions indefinitely. The equation of a line is given by,

y =mx + c

where,

x is the coordinate of the x-axis,

y is the coordinate of the y-axis,

m is the slope of the line, and

c is the y-intercept.

The graphs can be described as shown below.

A.) The first graph has the y-intercept at 2. Therefore, the first graph can be described by the equation, y =5x + 2.

B.) For the second graph, the graph passes through the point (-1,0). Therefore, if we substitute the value of y as 0 in the equation y=3x+3, we will get x=-1.

Hence, the equation of the second graph is y=3x+3.

C.) For the third graph, the graph passes through the point (-1.5,0). Therefore, if we substitute the value of y as 0 in the equation y=2x+3, we will get x=-1.5.

Hence, the equation of the second graph is y=2x+3.

Learn more about Equation of Line:

brainly.com/question/21511618

#SPJ1

4 0
2 years ago
determine an equation of a line in standard form that is perpendicular lo the line 2y = -x + 3 and passes through the point (4,
Nataliya [291]
First, i put the equation in y=mx+b by dividing 2, since its 2y. since it’s perpendicular we’re talking about you switch the sides (opposite reciprocals). the rest should be self explanatory.

4 0
3 years ago
Determine whether quadrilateral ABCD is a rhombus, a rectangle, a square, a parallelogram, or none. List all that apply. Explain
svlad2 [7]

Answer:

  • ABCD is a rhombus, and a parallelogram

==================================

<h3>Given </h3>

  • Points A(-6, - 1), B(4, - 6), C(2, 5), D(- 8, 10)

First, plot the points (see attached picture).

Then, connect all the points.

<h3>We see that:</h3>

  • Opposite sides are parallel,
  • Diagonals are perpendicular.

From our observation the figure is rhombus.

Let's confirm it with the following.

1) Find midpoints of diagonals and compare.

  • AC → x = (- 6 + 2)/2 = - 2, y = (- 1 + 5)/2 = 2
  • BD → x = (4 - 8)/2 = - 2, y = (- 6 + 10)/2 = 2

The midpoint of both diagonals is same (- 2, 2).

2) Find slopes of diagonals and check if their product is -1, this will confirm they are perpendicular.

  • m(AC) = (5 - (-1))/(2 - (-6)) = 6/8 = 3/4
  • m(BD) = (10 - (-6))/(-8 - 4) = - 16/12 = - 4/3

  • m(AC) × m(BD) = 3/4 * (- 4/3) = - 1

<u>Confirmed.</u>

So this is a rhombus and also a parallelogram but <u>not</u> rectangle or square, since opposite angles are not right angles.

5 0
1 year ago
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