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Arada [10]
3 years ago
6

Circle any conjugated portions in the molecules shown in(a - e). If no conjugation exists, write "no conjugation".

Chemistry
1 answer:
hodyreva [135]3 years ago
8 0

Answer: find the circled option in the attachment below. Only option a is " no conjugation"

Explanation: Conjugation is possible by means of alternating single and double bonds in which each atom supplies a p orbital perpendicular to the plane of the molecule. Therefore triple bonds doesn't show conjugation.

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Need help with this chemistry homework
Elza [17]

Answer:

10.0 ml and 35.0ml respectively

Explanation:

if A=10.0ml let B be x

Now,

Lets assume the pan is balanced

then,

x = 10.0 ml

Therefore B= 10.0 ml

[Repeat the same process in next question]

7 0
2 years ago
If the temperature of a piece of steel decreases, what happens to its density? a. The density decreases. b. The density increase
vampirchik [111]

Answer:

Explanation:

4 0
3 years ago
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Is heat a from of kinetic or potential energy?
Leni [432]

Answer:

its made up of both but I would probably say kinetic

Explanation:

3 0
3 years ago
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Carbon dioxide gas occupies a volume of 20.0 L at 308K and 2.30 atm. What volume would it occupy at 416 K and 5.40 atm?
Brrunno [24]

Answer : The final volume of gas is, 11.5 L

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 2.30 atm

P_2 = final pressure of gas = 5.40 atm

V_1 = initial volume of gas = 20.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 308 K

T_2 = final temperature of gas = 416 K

Now put all the given values in the above equation, we get:

\frac{2.30atm\times 20.0L}{308K}=\frac{5.40atm\times V_2}{416K}

V_2=11.5L

Therefore, the final volume of gas is, 11.5 L

7 0
3 years ago
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An -ite or -ate ending on the name of a compound indicates that the compound:
ololo11 [35]

Explanation:

I'm not sure what it is

4 0
3 years ago
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