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bazaltina [42]
2 years ago
13

What will happen to the wavelength of a wave if the frequency is left unchanged?

Chemistry
1 answer:
algol [13]2 years ago
6 0
Someone. or something will get hurt
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H2O+O2=H202, how would I balance this equation?
Sergio [31]

Answer:

2H2O2→2H2O+O2

Explanation:

This reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

Add 2 molecules of hydrogen peroxide and 2 molecules of water. Since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

2H2O2→2H2O+O2

8 0
2 years ago
I need an answer ASAP<br><br> What important role do sand dunes play?
Nezavi [6.7K]

Answer:

Keeps tides on the shore and away from the city

Explanation

6 0
2 years ago
Which of these factors influences air temperature?
Ksju [112]

Answer:

D

Explanation:

3 0
3 years ago
The density of H2O2 is 1.407 g/mL, and the density of O2 is 1.428 g/L. How many liters of O2 can be made from 55 mL H2O2
balandron [24]

Explanation:

mass H2O2 = 55 mL(1.407 g/mL) = 80.85 g

molar mass H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol

moles H2O2 = 80.85 g/34.02 g/mol = 2.377 moles H2O2

For each mole of H2O2 you obtain 0.5 mole of O2 (see the equation).

moles O2 = 2.377 moles H2O2 (1 mole O2)/(2 moles H2O2) = 1.188 moles O2

Now, you need the temperature.  If you are at STP (273 K, and 1.00 atm) then 1 mole of an ideal gas at STP has a volume of 22.4 L.  Without temperature you are not really able to continue.  I will assume you are at STP.

Volume O2 = 1.188 moles O2(22.4 L/mole) = 0.0530 L of O2.

which is  53 mL.

8 0
2 years ago
Describe the relationship between volume and temperature of an ideal gas
kvv77 [185]

Answer:

Explanation:

Here, we want to describe the relationship between the volume and temperature of an ideal gas

This relationship is defined by Charles' law

From this law, we know that the volume of a given mass of gas is directly proportional to its temperature at a fixed pressure

What this means is that as long as the pressure remains unchanged, when the volume increases, the temperature increases, and when the volume decreases, the temperature decreases

These can be represented by the mathematical formula below:

\frac{V_1}{T_1}\text{ = }\frac{V_2}{T_2}

8 0
1 year ago
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