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3 years ago

HELP WILL MARK YOU BRAINLIEST

Mathematics

1 answer:

-BARSIC- [3]3 years ago

6 0

Step-by-step explanation:

A school needs 2,2337 notepads. They come in packs of 20. This is a common question.

Start by finding out how many packs of 20 go into 2,337. This is done by doing the division 2337 ÷ 20. This finds the answer 116. The remainder is 17. Hmm. The school cannot buy 116 packs of notepads otherwise they would be 17 short ( the remainder), so they buy one extra pack-117 packs. This extra pack covers the extra 17, even though there are no packs of 17, only 20. This means they will have three spare.

The answer is 117 packs.

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Bruce rents snowmobiles to tourists.He charges $135 for 4 hours and $202.50 for 6 hours

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From which set of dimensions could a triangle be constructed?

lutik1710 [3]

The longest side of the triangle has to be less than the sum of the two other sides.

A ⇒ 7 + 8 = 15
B ⇒ 8 + 5 < 14
C ⇒ 6 + 3 < 10
D ⇒ 2 + 6 > 7

The answer is D, because the longest side length (7) is shorter than the two other side lengths (2 and 6).

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Find the area of a triangle with a base of 9 feet and hypotenuse length of 13 feet

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Answer:

42.21 ft^2

Step-by-step explanation:

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2 years ago

Suppose that prices of recently sold homes in one neighborhood have a mean of $265,000 with a standard deviation of $9300. Using

Hatshy [7]

Answer:

Range = (237100, 292900)

Step-by-step explanation:

Using Chebyshevs Inequality:

$P(|X - \mu | \le k \sigma )\ge 1 -\dfrac{1}{k^2}= 0.889$

$1 -\dfrac{1}{k^2}= 0.889$

$\dfrac{1}{k^2}= 1- 0.889$

$\dfrac{1}{k^2}=0.111$

$k = \sqrt{\dfrac{1}{0.111}}$

$k \simeq 3$

Thus, 88.9% of the population is within 3 standard deviation of the mean with the Range = μ ± kσ

where;

μ = 265000

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Range = 265000 ± 27900

Range = (265000 - 27900, 265000 + 27900)

Range = (237100, 292900)

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2 years ago

Systems of equations and inequalities<br> solving systems by elimination<br> {y= -x+1<br> {y= 4x-14

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Answer:

x = 3 , y = -2

Step-by-step explanation:

Solve the following system:

{y = 1 - x | (equation 1)

y = 4 x - 14 | (equation 2)

Express the system in standard form:

{x + y = 1 | (equation 1)

-(4 x) + y = -14 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -14 | (equation 1)

x + y = 1 | (equation 2)

Add 1/4 × (equation 1) to equation 2:

{-(4 x) + y = -14 | (equation 1)

0 x+(5 y)/4 = (-5)/2 | (equation 2)

Multiply equation 2 by 4/5:

{-(4 x) + y = -14 | (equation 1)

0 x+y = -2 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -12 | (equation 1)

0 x+y = -2 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 3 | (equation 1)

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Collect results:

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