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mezya [45]
2 years ago
11

ALGEBRA 1 HW< please help to give explanations

Mathematics
2 answers:
galben [10]2 years ago
7 0

Please refer the attached pictures.

Hope this helps! :D

Ronch [10]2 years ago
6 0

Answer:

See below

Step-by-step explanation:

a)

  • 11x^2 + x^2 = (4x + 8)(3x - 3)
  • 12x^2 = 12x^2 + 24x - 12x - 24
  • 12x - 24 = 0
  • 12x = 24
  • x = 2

b)

  • x/3 - x/9 = 6
  • 3x/9 - x/9 = 6
  • 2x/9 = 6
  • 2x = 54
  • x = 27

c)

  • 6^(x + 9) = 36^x
  • 6^(x + 9) = 6^(2x)
  • x + 9 = 2x
  • 2x - x = 9
  • x = 9

d)

  • 4/9 + 1/a = 2/3
  • 1/a = 2/3 - 4/9
  • 1/a = 6/9 - 4/9
  • 1/a = 2/9
  • a = 9/2

e)

  • √x + 3 = 6
  • x + 3 = 6^2
  • x = 36 - 3
  • x = 33

f)

1.2m - 0.2 = 3.8 + m

  • 1.2m - m = 3.8 + 0.2
  • 0.2m = 4
  • m = 4/0.2
  • m = 20

g)

  • (x + 12)^2 = 9
  • x + 12 = ± 3
  • x = ± 3 - 12
  • x = - 9, x = - 15
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<h2 /><h2>⟹</h2>

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

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Equation at the end of step3:

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STEP4:

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\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

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Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

Hence, there are 28 combinations and 20160 permutations.

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