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Brilliant_brown [7]
3 years ago
10

Solve for x: (5 points) -6/5x - 4 = -46

Mathematics
1 answer:
Alecsey [184]3 years ago
3 0

Answer:x5

Step-by-step explanation:Let's solve your equation step-by-step.

4x+2=2x+12

Step 1: Subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

Step 2: Subtract 2 from both sides.

2x+2−2=12−2

2x=10

Step 3: Divide both sides by 2.

2x

2

=

10

2

x=5

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ira [324]

Answer:

grading

A-1---80% AND ABOVE

A---70% AND ABOVE

SO 76.8/100=A

Step-by-step explanation:

I HOPE IT WILL HELP YOU

5 0
3 years ago
Read 2 more answers
The functions f(x) and g(x) are shown on the graph. fx)=x2<br> What is g(x)
ioda

It’s a flip of the graph on the x-axis

Therefore f(x) = - x^2 (NOT IN PARENTHESIS that would be a reflection on the y axis)

It’s a shift 4 y values down therefore

g(x) = - x^2 - 4

Credits to: <u>hoodini2</u>

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4 years ago
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3 years ago
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Determine whether the following statement is true or false. Justify your answer.
riadik2000 [5.3K]

Answer:

B. The statement is false. This is true only if θ is an acute angle in a right triangle.

Step-by-step explanation:

Trigonometric ratio formula can only be applied to define the relationship between the angles of a right triangle and its side lengths.

Therefore, it is impossible to define or find the tan θ of "any triangle". It only applies to right angled triangles.

In the case of a right triangle, given a reference angle, θ, tan θ = side lenght opposite to θ ÷ side lenght adjacent to θ (tan θ = \frac{opp}{adj}.

A right triangle has two acute angles and 1 right angle that which is 90°.

Therefore, we can conclude that:

"B. The statement is false. This is true only if θ is an acute angle in a right triangle."

3 0
3 years ago
Bill cut out 16 squares and 28 circles. He divided the cutouts into groups so that the same number of squares and circles were i
vlabodo [156]

Answer:

The greatest number of groups he could have made is 4 groups

Each of the four groups will have:

4 Squares each

7 circles each

Step-by-step explanation:

16 squares

28 circles

Find the highest common factor of 16 and 28

16: 1, 2, 4, 8, 16

28: 1, 2, 3, 4, 7, 14, 28

The highest common factor of 16 and 28 is 4

This means the greatest number of groups he could have made is 4 groups

Each of the four groups will have:

16 squares = 16 / 4

= 4 Squares each

28 circles = 28 / 4

= 7 circles each

Each of the four groups will have:

4 Squares each

7 circles each

7 0
4 years ago
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