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Brilliant_brown [7]

3 years ago

10

Solve for x: (5 points) -6/5x - 4 = -46

1 answer:

Alecsey [184]3 years ago

3 0

Answer:x5

Step-by-step explanation:Let's solve your equation step-by-step.

4x+2=2x+12

Step 1: Subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

Step 2: Subtract 2 from both sides.

2x+2−2=12−2

2x=10

Step 3: Divide both sides by 2.

2x

2

=

10

2

x=5

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A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. describe the possible lengths o

blagie [28]

The possible lengths of the garden would be all of the common factors of 1200.
1 , 1200
2 , 600
3 , 400
4 , 300
5 , 240
6 , 200
7 , 171.43
8 , 150
9 , 133.33
10 . 120
11 . 109.09
12. 100
13. 92.31
14. 85.71
15. 80
16. 75
17. 70.59
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19. 63.15
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5 0

3 years ago

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A rock dropped on the moon will increase its speed from 0 m/s (its starting

belka [17]

<h2>Hello!</h2>

The answer is:

The correct option is the option D

$g=1.63\frac{m}{s^{2}}$

<h2>Why?</h2>

To calculate the acceleration, we need to use the following formula that involves the given information (initial speed, final speed, and time).

We need to use the following free fall equation:

$V_{f}=V_{o}-g*t$

Where:

$V_{f}$ is the final speed.

$V_{o}$ is the initial speed.

g is the acceleration due to gravity.

t is the time.

We are given the following information:

$V_{f}=8.15\frac{m}{s}$

$V_{o}=0\frac{m}{s}$

$t=5seconds$

Then, using the formula to isolate the acceleration, we have:

$V_{f}=V_{o}-g*t$

$V_{f}=V_{o}-g*t\\\\g*t=V_{o}-V_{f}\\\\g=\frac{V_{o}-V_{f}}{t}$

Now, substituting we have:

$g=\frac{V_{o}-V_{f}}{t}$

$g=\frac{0-8.15\frac{m}{s}}{5seconds}=-1.63\frac{m}{s^{2}}$

Therefore, since we are looking for a magnitude, we have that the obtained value will be positive, so:

$g=1.63\frac{m}{s^{2}}$

Hence, the correct option is the option D

$g=1.63\frac{m}{s^{2}}$

Have a nice day!

7 0

2 years ago

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Murrr4er [49]

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3 years ago

What is 78.867 ÷0.9 ANSWER FAST!!

xeze [42]

Answer:87.63

Step-by-step explanation:

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cestrela7 [59]

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