3 years ago

You have been assigned a 9-digit identification number. How many identification numbers are possible?

1 answer:

3 0

Permutations are all possible variations, in which a set of numbers or characters can be ordered. The number of permutations on a set of n elements is given by n!. In our case we have 9 digits, which means 9 elements.
There are 9!=9*8*7*6*5*4*3*2*1=362880 possible variations, or 362880 possible identification numbers.

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Marrrta [24]

The square root of integers where one can get the number 2.71 will be between 7 and 8.

The square root of integers where one can get the π will be between 9 and 10

<h3>How to illustrate the value?</h3>

It should be noted that the square of a number simply means multiplying the number by itself.

Therefore, the.square root of integers where one can get the number 2.71 will be between 7 and 8.

Also, the square root of integers where one can get the π will be between 9 and 10

Learn more about computations on:

brainly.com/question/4658834

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