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NNADVOKAT [17]
3 years ago
14

You have been assigned a 9-digit identification number. How many identification numbers are possible?

Mathematics
1 answer:
Rasek [7]3 years ago
3 0
Permutations are all possible variations, in which a set of numbers or characters can be ordered. <span>The number of permutations on a set of </span><span> n elements is given by </span><span> n!. </span>In our case we have 9 digits, which means 9 elements. 
There are 9!=9*8*7*6*5*4*3*2*1=362880 possible variations, or 362880 possible identification numbers.
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Answer:true

Step-by-step explanation:

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3 0
3 years ago
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NEED HELP WILL GUVE 5 stars
Bumek [7]

Answer:

m=15

Step-by-step explanation:

m/9 + 2/3    

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6 0
3 years ago
What is the probability of selection for any man in a proportionate random sample, where a sample of 100 will be drawn from a po
kolbaska11 [484]
Working Principle: Stratified Random Sampling

nx = (Nx/N)*n

where:
    nx = sample size for stratum x
    Nx = population size for stratum x
    N = total population size 
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Given:

  Nx = 100
  N = 1000
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Solution:

nx = (Nx/N)*n
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ny = (Nx/N)*n
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<em>ANSWER: 50%</em>
7 0
3 years ago
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arlik [135]

Answer:

Step-by-step explanation:

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6 0
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Svetlanka [38]

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3 0
2 years ago
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