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Mademuasel [1]
3 years ago
7

There are 90 girls and 60 boys in the sixth grade at a middle school. Of these students, 7 girls and 2 boys write left-handed. W

hat percentage of the sixth graders at this middle school write left-handed?
Mathematics
2 answers:
matrenka [14]3 years ago
7 0

Step-by-step explanation: Ok so if there are 90 girls and 7 are left handed u  use this method 6/90 multiply by 100 and u get 7.77%

Radda [10]3 years ago
6 0

Answer:

6%

Step-by-step explanation:

  1. 90 + 60 = 150
  2. 7 + 2 = 9
  3. Set up a proportion: \frac{9}{150} = \frac{x}{100}  
  4. Cross multiply, then divide: 9 × 100 = 900, 900 ÷ 150 = 6
  5. So, 6% of students in 6th grade were left-handed

I hope this helps!

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Randomization is important to ensure that both groups are roughly equivalent regarding students’ preparedness, anxiety levels, and study skills.

<h3>What is randomization in an experiment?</h3>

Randomization is when subjects in an experiment are placed in either the control group or the treatment group without any structure. They are placed in either groups randomly. The purpose of randomization is to ensure that subjects in either group are homogenous.

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3 0
1 year ago
According to the graph, how far did the object move between the second and third seconds?
Setler79 [48]

Answer:

Your answer would be B

Step-by-step explanation:

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Hope this helps you out!! Have a good day:))

7 0
2 years ago
X+3y=23<br> x-2y=-17 <br> elimaiton
VMariaS [17]
<h2><u>ANSWER</u></h2>

y = 8

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Step-by-step explanation:

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6 0
2 years ago
I just want to make sure this is accurate!! Thanks
egoroff_w [7]

Answer:

Looks good to me!

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
f(x) = square root ( x^4 -16x^2) let f be the function given by: . . a) Find the domain of f.. b) Find f '(x). c) Find the slope
Bond [772]
A ) The domain:
x^{4} -16 x^{2}  \geq 0 \\  x^{2} ( x^{2} -16) \geq 0 \\  x^{2} -16 \geq 0 \\  x^{2}  \geq 16
x ≤ -4  and x≥ 4  or:  x ∈ ( - ∞ , - 4 ) ∪ ( 4  , + ∞ )
b ) f ` ( x ) = \frac{1}{2 \sqrt{ x^{4} -16 x^{2} } } *( 4 x^{3} - 32 x ) = \\ = \frac{2x( x^{2} -8)}{ \sqrt{ x^{4}-16 x^{2}  } }
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m = -1 / f `(x)
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m = - 3/34 

8 0
3 years ago
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