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Tresset [83]
3 years ago
7

Which function has a range of y < 3? y - 3(2) y = 2(3) O y=-(2)x+ 3 Oy- (2) * - 3

Mathematics
1 answer:
defon3 years ago
6 0

Given:

The range of a function is y.

To find:

The function for the given range from the given options.

Solution:

In option A, the given function is:

y=3(2)^x

Here, (2)^x is always greater than 0. So, 3(2)^x is also greater than 0, i.e., y>0.

In option B, the given function is:

y=2(3)^x

Here, (3)^x is always greater than 0. So, 2(3)^x is also greater than 0, i.e., y>0.

In option C, the given function is:

y=-(2)^x+3

Here,

(2)^x>0

-(2)^x

-(2)^x+3

y

The range of this function is y. So, option C is correct.

In option D, the given function is:

y=(2)^x-3

Here,

(2)^x>0

(2)^x-3

y

The range of this function is y

Therefore, the correct option is only C.

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\bf \textit{using the pythagorean theorem}&#10;\\\\&#10;c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b&#10;\qquad&#10;\begin{cases}&#10;c=\stackrel{10}{hypotenuse}\\&#10;a=\stackrel{9.25}{adjacent}\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;\sqrt{10^2-9.25^2}=b\implies \sqrt{14.4375}=b\implies 3.8\approx b


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