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Korvikt [17]
3 years ago
13

Which of these signs suggests that a male client with the syndrome of inappropriate antidiuretic hormone (SIADH) secretion is ex

periencing complications? A Tetanic contractions B Neck vein distention C Weight loss D Polyuria
Medicine
1 answer:
Dvinal [7]3 years ago
4 0

Answer:

Option B (Neck vein distention) is the correct choice.

Explanation:

  • SIADH accumulation induces overconsumption of the antidiuretic hormone, leading to insulin resistance. Significant SIADH could lead to problems including certain overloading of the vascular fluid, indicated by obstruction of the neck vein.  
  • No tetanic contractions interact with that kind of condition. It can give rise to excess weight as well as water retention.

Some other available scenarios in question are not relevant to just the given circumstance. But the above is indeed the correct one.

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An AED is in use and has indicated that a shock is needed, the second rescuer should start compressions immediately after delivering the shock to the individual.

<h3>What is CPR?</h3>

This is referred to as Cardiopulmonary resuscitation and is an emergency lifesaving technique performed when the heart stops beating.This include series of compressions and artificial ventilation so as to ensure the brain functions are preserved.

In the case where an automated external defibrillator (AED) is used and indicates a shock is needed, it is best to give it immediately.

This should then be followed by compressions from the second rescuer which is therefore the reason why it was chosen as the correct choice.

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3 years ago
A person is considered legally intoxicated in most states with a blood alcohol level of 80.0 mg/dl. calculate this concentration
Furkat [3]

The concentration expressed in parts per million is 782 ppm.

<h3>What is Parts per million?</h3>

It is calculated by dividing the mass of the solution by the mass of a solute present in one million (10⁶) parts.

<h3>Calculation for units in ppm:</h3>

Given:

Mass of  blood alcohol =  80 mg/dL = 80 x 10^{5} g/mL

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Concentration in ppm = (Mass of alcohol/Mass of plasma) x 10^{6}

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Answer:

2.5 (B)

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