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MissTica
3 years ago
10

assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. the growth in the scale of motorcycle

s is 16% every year and that of cars is 25% every year. Find when the sale of cars will be more then the sale of motorcycles. shw your work
Mathematics
1 answer:
USPshnik [31]3 years ago
3 0

<em>Answer:</em>

<em>Final answer is approx 6.644 years.</em>

<em>Step-by-step explanation:</em>

<em>Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year. </em>

<em> </em>

<em>So we can use growth formula:</em>

<em>A = P (1 + r)^t</em>

<em></em>

<em>Then we get equation for motorcycles and cars as:</em>

<em>A = 5.75 (1 + 0.16)^t</em>

<em>A = 3.5 (1 + 0.25)^t</em>

<em></em>

<em>Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:</em>

<em>3.5 (1 + 0.25)^t > 5.75 (1 + 0.16)^t</em>

<em>3.5 (1.25)^t > 5.75 (1.16)^t</em>

<em>3.5 (1.25)t . 5.75 (1.16)^t</em>

<em />

<em>(1.25)^t/(1.16) > 5.75/3.5</em>

<em>(1.25/1.16)^t > 1.64287514286</em>

<em />

<em>t·In (1.25/1.16) > In (1.64287514286)</em>

<em>t > In(1.64285714286)/In (1.25/1.16)</em>

<em>t > 6.6436473051</em>

<em />

<em>Hence final answer is approx 6.644 years.</em>

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Given

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