The answer to this question is that the percentage by volume of a hyrdrogen peroxide in mostly first aid kits contains 3%. Hydrogen peroxide or H2O2 is a compound that can be used as an antiseptic in orderto prevent infections from spreading in the bruises, cuts, and even burns. Hydrogen peroxide can also be used as a bleaching agent and an oxidizer.
Answer: salt
Explanation:
Arrhenius acids are substances which dissociate in water to give 
ions.
Arrhenius bases are substances which dissociate in water to give 
ions.
Thus when they combine, they neutralize each other and produce salt and water.
Answer:
38.3958 °C
Explanation:
As,
1 gram of carbohydrates on burning gives 4 kilocalories of energy
1 gram of protein on burning gives 4 kilocalories of energy
1 gram of fat on burning gives 9 kilocalories of energy
Thus,
27 g of fat on burning gives 9*27 = 243 kilocalories of energy
20 g of protein on burning gives 4*20 = 80 kilocalories of energy
48 gram of carbohydrates on burning gives 4*48 = 192 kilocalories of energy
Total energy = 515 kilocalories
Using,
Given: Volume of water = 23 L = 23×10⁻³ m³
Density of water= 1000 kg/m³
So, mass of the water:
Mass of water = 23 kg
Initial temperature = 16°C
Specific heat of water = 0.9998 kcal/kg°C
Solving for final temperature as:
<u>Final temperature = 38.3958 °C </u>
Answer:
Pinagsisikapan kong gawin ang pinakamahusay na tao na maaari akong maging
Answer:
94.57 g H2O
Explanation:
32.0 g H2
Molar Mass H2: 2.01 g/mol
84.0 g O2
Molar Mass O2: 32.00 g/mol
Molar Mass H2O: 18.02 g/mol
First balance the eqution:
2H2 + O2 = 2H2O
Find the amount of moles that both 32.0 g of H2 and 84.0 g of O2 can produce using the molar masses:
32.0 g H2 x ((1 mole H2)/ (2.015 g H2)) = 15.88 moles H2
84.0 g O2 x ((1 mole O2)/(32.00 g O2)) = 2.63 moles O2
Now you can find the amount of grams of H2O each reactant will produce:
**keep in mind of mole ratios from balanced equation**
15.88 moles H2 x ((2 moles H2O)/(2 moles H2)) x ((18.015 g H2O)/(1 mole H2O) =286.07 g H2O
2.63 moles O2 x ((2 moles H2O)/(1 mole O2)) x ((18.015 g H2O)/(1 mole H2O) = 94.76 g H2O
94.76 is the final answer because this is the limiting reactant, meaning it produces less product than the H2 so it limits the reaction from producing anymore product from the amount calculated.
