Answer:
Some of the properties of cobalt silicate include:
It occurs as a crystal with red- violet type colour.
The shape of the cobalt silicate crystal is orthorhombic.
The molecular weight of cobalt silicate is 209.95.
The melting temperature of Cobalt Silicate is 1618 degrees Celsius.
The density of Cobalt Silicate is 4.63 grams per centimetre cube.
Cobalt Silicate can serve as a semi-conductor.
Answer:
This new temperature is 97.7 mL
Explanation:
Step 1: Data given
Volume = 0.225 L
STP = 1 atm and 273 K
Pressure = 2.7 atm
Temperature = 320 K
Step 2: Calculate new volume
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the pressure at STP = 1 atm
⇒with V1 = the volume = 0.225 L
⇒with T1 = the temperature at STP = 273 K
⇒with P2 = the new pressure = 2.7 atm
⇒with V2 = the new volume = TO BE DETERMINED
⇒with T2 = the new temperature = 320 K
(1atm *0.225 L)/273 K = (2.7 atm * V2) /320 K
8.24 * 10^-4 = 2.7 * V2 / 320K
2.7V2 = 0.264
V2 = 0.0977 L = 97.7 mL
This new temperature is 97.7 mL
Answer:
1.9 x 10⁻¹³M
Explanation:
Given 0.027M Ca(OH)₂(aq) => 0.027M Ca⁺²(aq) + 2(0.027M) OH⁻(aq)
2(0.027M) OH⁻(aq) = 0.054M OH⁻(aq).
from [H⁺][OH⁻] = 1 x 10⁻¹⁴ at STP Conditions (0°C, 1Atm)
∴{H⁺] = [H₃O⁺] = (1 x 10⁻¹⁴/0.054)M = 1.85 x 10⁻¹³M or 1.9 x 10⁻¹³at 0°C & 1Atm pressure.
