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ad-work [718]
3 years ago
14

Question 6(Multiple Choice Worth 3 points)

Chemistry
2 answers:
mihalych1998 [28]3 years ago
4 0

Answer:

Plateau

Explanation:

i think

iris [78.8K]3 years ago
3 0
All of the above, is that an answer?
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A solution of barium nitrate has 61.2g of barium nitrate in 1 liter of solution. How many mg of barium are there in 7.5 quarts
Nuetrik [128]

Answer:

220.44g Ba²⁺ ions in solution

Explanation:

Given parameters:

Mass of barium nitrate = 61.2g

Volume of solution = 1 liter

Unkown:

Mass of barium in 7.5quarts of solution?

Solution

We must first convert quarts to its liter equivalence:

                    1 quarts = 0.95 liter

                   7.5 quarts = 0.95 x 7.5; 7.125liter

Now, let us find the mass of barium nitrate in a solution of 7.125liter:

        Given:

            1 liter of solution contains 61.2g of barium nitrate:

          7.125 liter will contain  7.125 x 61.2 = 436.05g of barium nitrate.

The formula of the compound is Ba(NO₃)₂:

  In solution we have  Ba²⁺ + NO₃⁻

                Ba(NO₃)₂ → Ba²⁺ + 2NO₃⁻

 

Number of moles of Ba(NO₃)₂ = \frac{mass of Ba(NO₃)₂}{Molar mass of Ba(NO₃)₂}

Molar mass of Ba(NO₃)₂ = 137 + 2[14 + 3(16)] = 271g/mol

Number of moles of Ba(NO₃)₂ = \frac{436.05}{271} = 1.609mole

      1 mole of Ba(NO₃)₂ will produce 1 mole of Ba²⁺ ions in solution

    therefore, 1.609mole of Ba(NO₃)₂ will also yield 1.609mole of Ba²⁺ ions in solution

Mass of Ba²⁺ ions = Number of moles of Ba²⁺ ions  x molar mass of Ba²⁺ ions

Mass of Ba²⁺ ions = 1.609 x 137 = 220.44g

3 0
3 years ago
11C. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solut
Llana [10]

For the reactants,

  • The oxidation number of hydrogen = +1
  • The oxidation number of oxygen = -2
  • The oxidation number of arsenic = +5
  • The oxidation number of carbon = +3

For the products,

  • The oxidation number of hydrogen = +1
  • The oxidation number of oxygen = -2
  • The oxidation number of arsenic = +3
  • The oxidation number of carbon = +4

Here, arsenic (+5 to +3) and carbon (+3 to +4) are the only oxidation numbers changing.

Note that an increase in oxidation number means electrons are lost. Thus oxidation is occurring, and a decrease in oxidation number means electrons are being gained, and thus reduction is occurring.

Also, the compound that contains the element being oxidized is the reducing agent, and the compound that contains the element being reduced is the oxidizing agent.

So, the answers are:

name of the element oxidized: Carbon

name of the element reduced: Arsenic

formula of the oxidizing agent: \text{H}_{3}\text{AsO}_{4}

formula of the reducing agent: \text{H}_{2}\text{C}_{2}\text{O}_{4}

6 0
1 year ago
(Chemistry) Match each item with the correct statement below.
Colt1911 [192]

Number\;1:\;Formula.\\\\Number\;2:\;Solution\\\\Number\;3:\;Chemistry\\\\Number\;4:\;Solute\\\\Number\;5:\;Mass\\\\Number\;6:\;Matter\\\\Number\;7:\;Alloy\\\\Number\;8:\;Aqueous\\\\Number\;9:\;Quantitative

4 0
2 years ago
Does ultraviolet block sunburn
satela [25.4K]

Answer:

no

Explanation:

8 0
3 years ago
Calculate the concentration of each species in a 0.240 m c6h5nh3cl solution.
amm1812
The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+ 
K = Kw/ Kb= 1.0 x 10^-14 / 3.8 x 10^-10= 2.6 x 10^-5 

=2.6 x 10^-5 = x^2 / 0.240-x 
x = [H3O+] = 0.00251 M 
pH = 2.60 is the concentration
8 0
2 years ago
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