The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Answer:
41.802 feet
Step-by-step explanation:
Given that a 92 ft path cuts diagonally from Mateo St. to Cove St. It makes an angle of 68° with Cove St. and an angle of 34° with Mateo St.
We can visualize a triangle formed by the three streets One side is 92 feet.
Angle opposite 92 feet = 
Let x be length of Cove st and y length of Mateo st.
Using sine angle for triangles,
Simplify to get
x=52.595
y=87.207
Distance saved= 
Answer:
(3x/4) + 4
Step-by-step explanation:
convert al to decimal and then add
1.25 + 0.75 +0 .4 + 2x 0.375 + 1.6
Answer:
3 × 10 = 30 2 ×5 = 10
Step-by-step explanation:
30 + 10 = 40 rolls
Answer:
10 weeks
Step-by-step explanation:
