I just learn this but I forgot
Answer:
t=1.283 seconds and
0.779 seconds
Step by step Explanation:
Given: h=18 ft
The given equation is h=2+33t-16t²
Then if we substitute the value of given h, h=18 ft into the given equation we have,
18=2+33t-16t²
Then if we re- arrange we have
16t²−33t+16=0
We can see that the above quadratic equation is in standard form, with a=16, b=33 and c=16 then we can use quadratic formula in solving it which is
t= −(−33±√[(−33) ²−4×16×16)]/(2×16)
= [33±√[1089−1024]/(32)
= [33±√[65]/(32)
=1.283 or 0.779 seconds
the two real roots , of the quadratic are:
1.283 and
0.779 seconds
t= 1.283 or 0.779 seconds
Hence, the ball is at 18 feet with height 0.779seconds after it has been thrown up and,
and is at 21 feet with height 1.283 seconds after after thrown down
Answer:
25/32 chapter per hour
Step-by-step explanation:
(5/8)/(4/5)=x/1
cross product
4/5*x=(5/8)(1)
4/5x=5/8
x=(5/8)/(4/5)
x=(5/8)(5/4)
x=25/32
<span> line passes through the points (p, a) and (p, –a)
where p and a are real numbers and p ≠ 0
(p, a) and (p, –a) m = Cannot divide by ZERO, there is no slope to this Line.
slope of the line: no slope (does not exist)
equation of the line: x = p Perpendicular Line
</span><span>slope of a line perpendicular to the given line: would be m = 0, horizontal Line y= 3
</span>y- intercept: none
Put all the x together and add the whole number. This is what U will get
