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3 years ago

Find the IQR of the data set

Mathematics

1 answer:

Phoenix [80]3 years ago

5 0

Find median, in this group median is 1
find Q1 which is median of lower half, in this group Q1 = 1/4

find Q3, which is median of upper half, in this group Q3 = 5/4

IQR is Q3-Q1

IQR = 5/4 - 1/4 = 4/4 = 1

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-32=4(y-5)-7y solve for y

Savatey [412]

Answer:

y= 4

Step-by-step explanation:

-32= 4(y -5) -7y

Expand:

-32= 4y -20 -7y

Simplify:

-32= -3y -20

+20 on both sides:

20 -32= -3y

Simplify:

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Divide both sides by -3:

y= -12 ÷(-3)

y= 4

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3 years ago

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Over [174]

Answer:

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Step-by-step explanation:

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3 years ago

Find a homogeneous linear differential equation with constant coefficients whose general solution is given by

frez [133]

Answer:

$y" + 2y' + 2y = 0$

Step-by-step explanation:

Given

$y=c_1e^{-x}cosx+c_2e^{-x}sinx$

Required

Determine a homogeneous linear differential equation

Rewrite the expression as:

$y=c_1e^{\alpha x}cos(\beta x)+c_2e^{\alpha x}sin(\beta x)$

Where

$\alpha = -1$ and $\beta = 1$

For a homogeneous linear differential equation, the repeated value m is given as:

$m = \alpha \± \beta i$

Substitute values for $\alpha$ and $\beta$

$m = -1 \± 1*i$

$m = -1 \± i$

Add 1 to both sides

$m +1= 1 -1 \± i$

$m +1= \± i$

Square both sides

$(m +1)^2= (\± i)^2$

$m^2 + m + m + 1 = i^2$

$m^2 + 2m + 1 = i^2$

In complex numbers:

$i^2 = -1$

So, the expression becomes:

$m^2 + 2m + 1 = -1$

Add 1 to both sides

$m^2 + 2m + 1 +1= -1+1$

$m^2 + 2m + 2= 0$

This corresponds to the homogeneous linear differential equation

$y" + 2y' + 2y = 0$

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3 years ago

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saveliy_v [14]

Answer:

14x-2 is answer

Step-by-step explanation:

may be this is helpful!

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3 years ago

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